我需要两个输入不同类型:
<input type="button" **onclick = "?????"** name="back" value="← Back" >
<input type="submit" name="submit" value="Forward →" >
我怎么能为type = button运行这个php代码:
<?php
if (isset($_POST['back']))
{
$_SESSION['onpage'] = $_SESSION['onpage'] - 1;
$query_questionset = "
select Q.Constructor AS Constructor,
QS.QuestionIDFKPK AS QuestionIDFKPK,
Q.QuestionValue AS QuestionValue,
QS.SortOrder AS SortOrder,
QS.onpage AS onpage
from tbluserset AS US
inner join tblquestionset AS QS ON US.QuestionSetIDFKPK = QS.QuestionSetIDPK
inner join tblquestion AS Q ON QS.QuestionIDFKPK = Q.QuestionIDPK
where (US.UserIDFKPK = " . $UserId . ")
and (US.UserSetIDPK= '" . $_SESSION['UserSetIDPK'] . "')
and (QS.onpage = '" . $_SESSION['onpage'] . "')
order by QS.SortOrder";
}
$QuestionSet_Constructors = mysql_query($query_questionset);
?>
我的表单和输入提交工作完美:
<form id= "formID" class="formular" method="post" action= "<?= $url = "QUESTIONAREnewdatabase.php"; ?>" accept-charset="utf-8">
我需要在input type=button
上运行php代码和操作表单,如果Back有type=submit
?
答案 0 :(得分:0)
试试这个
< input type="submit" onclick = "?????" name="back" value="← Back" >
答案 1 :(得分:0)
<form action="" id="formID" class="formular" method="post" accept-charset="utf-8">
<!-- Your inputs here -->
<button type="submit" name="back">← Back</button>
<button type="submit" name="submit">Forward →</button>
</form>
答案 2 :(得分:0)
这是使用Javascript的一种方式,这将动态创建并向表单附加名为back
的隐藏输入,然后提交表单 - 单击后退按钮时。
<script>
function postBack()
{
var myForm = document.getElementById("formID");
var backInput = document.createElement("input");
backInput.type = "hidden";
backInput.name = "back";
backInput.value = "1";
myForm.appendChild(backInput);
myForm.submit();
}
</script>
<input type="button" onclick="postBack()" name="back" value="← Back">
在服务器端,您现在可以测试:
if(isset($_POST['back']))
{
// back was pressed...
}