Question

如何从SELECT查询顶部返回一定数量的行？

我的意思是，假设我有一个1000行的表。假设我想要前50行，那么我想要第二行50行，然后是第三行50行，依此类推。我知道TOP或LIMIT会限制返回的行数，但我不确定如何告诉SQL从返回表中的某一点获取行。

Answer 1

在Sql server中，您可以使用ROW_NUMBER()函数来执行您想要的操作

SELECT ROW_NUMBER() OVER(ORDER BY col3 DESC) AS Row, 
    col1, col2, col3
FROM tablename

简而言之

WITH ctetable AS
(
    SELECT ROW_NUMBER() OVER(ORDER BY col3 DESC) AS RowNumber , 
        col1, col2, col3
    FROM tablename 
) 
SELECT * 
FROM ctetable 
WHERE RowNumber BETWEEN 1 AND 50;

Answer 2

SELECT TOP 50 * FROM 
(
    SELECT ROW_NUMBER() OVER(ORDER BY ID DESC) AS [Index], * FROM MyTable
) AS A
WHERE A.[Index] BETWEEN @StartIndex AND @EndIndex

Answer 3

;With CTE as(SELECT ROW_NUMBER() OVER(ORDER BY (select 0)) AS rno, * FROM MyTable)

select * from CTE where rno between start and end;

从顶部返回一定数量的结果

3 个答案: