我没有使用已知的点符号访问深层对象,而是想做相反的事情:从深层对象的键构建点符号字符串。
所以给出以下JSON对象:
{
great:{
grand:{
parent:{
child:1
},
parent2:1
}
}
}
我想获得以下数组路径:
[
"great.grand.parent.child",
"great.grand.parent2"
]
提前致谢!
答案 0 :(得分:6)
试试这个。但我不知道你为什么需要这个。
function path(a) {
var list = [];
(function(o, r) {
r = r || '';
if (typeof o != 'object') {
return true;
}
for (var c in o) {
if (arguments.callee(o[c], r + "." + c)) {
list.push(r.substring(1) + "." + c);
}
}
return false;
})(a);
return list;
}
var a = {
great:{
grand:{
parent:{
child:1
},
parent2:1
}
}
};
console.log(JSON.stringify(path(a)));
答案 1 :(得分:1)
var path = function (a) {
var list = [];
(function(o, r) {
r = r || '';
if (_.isArray(o)) {
return true;
}
for (var c in o) {
if (arguments.callee(o[c], r + (r!=""?"[":"") + c + (r!=""?"]":""))) {
list.push(r + (r!=""?"[":"") + c + (r!=""?"]":""));
}
}
return false;
})(a);
return list;
};
输入类似这样的东西(输入错误的深JSON对象):
{
"email": [
"Enter a valid email."
],
"billing": {
"name": [
"Enter a billing name."
],
"line1": [
"Enter a street address or PO box."
],
"city": [
"Enter a city."
],
"state": [
"Enter your state abbreviation."
],
"zip": [
"Enter a valid 5-digit zip."
]
},
"shipping": {
"name": [
"Enter a billing name."
],
"line1": [
"Enter a street address or PO box."
],
"city": [
"Enter a city."
],
"state": [
"Enter your state abbreviation."
],
"zip": [
"Enter a valid 5-digit zip."
]
},
"payment": {
"number": [
"Enter a valid credit card number."
],
"exp_month": [
"Enter a valid expiration month."
],
"exp_year": [
"Enter a valid expiration year."
],
"cvc": [
"Enter a valid CVC."
]
}
}
你得到这样的输出(数组表示法中的输入名称,通过客户端模板附加错误)
["email", "billing[name]", "billing[line1]", "billing[city]", "billing[state]", "billing[zip]", "shipping[name]", "shipping[line1]", "shipping[city]", "shipping[state]", "shipping[zip]", "payment[number]", "payment[exp_month]", "payment[exp_year]", "payment[cvc]"]