大家。 我正在尝试为Android制作基本的大亨游戏 我试图用计时器每隔5秒增加一次文本视图的值, 但是textview没有更新。 到目前为止,这是我的代码:
public class Town extends Activity implements OnClickListener {
Timer timer;
TimerTask task;
TextView goldTV;
TextView woodTV;
TextView foodTV;
TextView stoneTV;
TextView cashTV;
int gold = 20;
int wood = 20;
int food = 20;
int stone = 20;
int cash = 200;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_town);
goldTV = (TextView) findViewById(R.id.textView1);
woodTV = (TextView) findViewById(R.id.TextView01);
foodTV = (TextView) findViewById(R.id.TextView02);
stoneTV = (TextView) findViewById(R.id.TextView03);
cashTV = (TextView) findViewById(R.id.TextView04);
timer = new Timer();
task = new TimerTask() {
@Override
public void run() {
gold++;
goldTV.setText(gold);
try {
this.wait(2000);
}
catch (InterruptedException e){
}
}
};
}
@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub
}
}
答案 0 :(得分:4)
使用run()
方法
@Override
public void run() {
gold++;
goldTV.setText(gold);
try {
this.wait(2000);
}
catch (InterruptedException e){
}
}
您正在呼叫setText(int resId)
而不是setText(CharSequence c);
要显示实际的整数gold
,请将其从int
转换为String
String goldStr = String.valueOf(gold);
goldTV.setText(goldStr);
答案 1 :(得分:3)
您的问题是您正在更改UI线程以外的其他内容。更好的是在UI线程上运行它。另外,您应该将您的号码转换为字符串,否则Android会认为您正在寻找资源ID。把它们放在一起,然后......
task = new TimerTask() {
@Override
public void run() {
gold++;
runOnUiThread(new Runnable(){
public void run(){
goldTV.setText(""+gold);
}
});
try {
this.wait(5000);
}
catch (InterruptedException e){
}
}
};
甚至更好,您可以使用处理程序,如下所示:
Handler handler = new Handler();
Runnable task=new Runnable(){
public void run(){
handler.postDelayed(this,5000);
goldTV.setText(""+gold);
}
});
handler.postDelayed(task,5000);
答案 2 :(得分:1)
TimerTask应该与Timer对象一起使用。在您的代码中,您永远不会运行任务。
修改强> 试试这个:
goldTV.postDelayed(new Runnable() {
@Override
public void run() {
gold++;
goldTV.setText(gold+"");
goldTV.postDelayed(this,2000);
}
}, 2000);