我有一个PictureBox图像,其形式随着面板上的鼠标移动而移动。
它正在我想要它移动,但它一直闪烁(如刷新)并且我了解到它是表格的问题。
我在表单的构造函数中尝试了以下代码行,但没有成功:
SetStyle( ControlStyles.ResizeRedraw, true );
SetStyle( ControlStyles.UserPaint, true );
SetStyle( ControlStyles.AllPaintingInWmPaint, true );
SetStyle( ControlStyles.OptimizedDoubleBuffer, true );
这是鼠标移动的事件处理程序,如果它有助于查看所有图片。 chipHolder是一个面板,图像是分别从文件导入的图像。
private void grid_MouseMove(object sender, MouseEventArgs e)
{
columnPosition = e.X;
if (columnPosition != -1)
{
if (!(columnPosition < 35 || columnPosition > 610))
{
chipHolder.Controls.Clear();
PictureBox picBox = new PictureBox();
chipHolder.Controls.Add(picBox);
picBox.Image = image;
picBox.Width = image.Width;
picBox.Height = image.Height;
picBox.Location = new Point(columnPosition - 33, 0);
picBox.Show();
}
}
chipHolder.Update();
}
有什么想法吗?
答案 0 :(得分:4)
不要重新创建PictureBox
,只需移动它。
试过这个,图像移动没有任何闪烁:
private void button1_Click(object sender, EventArgs e)
{
for (int iter = 0; iter < 500; iter++)
{
pictureBox1.Location = new Point(pictureBox1.Left + 1, pictureBox1.Top + 1);
Application.DoEvents();
System.Threading.Thread.Sleep(30);
}
}
对于鼠标移动:
private void Form1_MouseMove(object sender, MouseEventArgs e)
{
pictureBox1.Location = new Point(e.X, e.Y);
}
private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
pictureBox1.Location = new Point(e.X + pictureBox1.Left, e.Y + pictureBox1.Top);
}
答案 1 :(得分:0)
伊戈尔所说的话:
private void grid_MouseMove(object sender, MouseEventArgs e)
{
columnPosition = e.X;
if (columnPosition != -1)
{
if (!(columnPosition < 35 || columnPosition > 610))
{
PictureBox picBox = chipHolder.Controls[0] // whatever your picbox id is;
picBox.Location = new Point(columnPosition - 33, 0);
}
}
}