Question

想象一下两张表sites＆amp; buildings，网站可能包含多个建筑物。我有一个查询，它为地理数据映射生成一个xml，并尝试使用LISTAGG函数来添加属于某个站点的所有建筑物。

在添加建筑物之前进行查询

SELECT XMLELEMENT("rss", 
            XMLATTRIBUTES('http://www.georss.org/georss' AS "xmlns:georss"),
                    XMLELEMENT("channel",
                                 XMLAGG(XMLELEMENT("item",
                                                   XMLFOREST(title AS "title",
                                                              description AS "description",
                                                              point AS "georss:point"))))).EXTRACT('/*')
    FROM (SELECT trim(s.sitedesc) AS title, 
          'Employee Count: ' || s.sitefte || '. Bldg Gross SF: ' || s.bldgarea || '. ' || CASE WHEN s.leasestat = '0' THEN 'Owned' WHEN s.leasestat = '1' THEN 'Leased, end date: ' || trim(l.edate) END AS description, 
          trim(s.latitude) || ' ' || trim(s.longitude) AS point
          FROM site s, leases l
          WHERE s.sold <> 1
            AND s.longitude != ' '
            AND s.sitecode = l.sitecode
        )

我可以让LISTAGG功能独立工作。

SELECT LISTAGG(trim(b.bldgcode)||' '||trim(b.bldgdesc), ', ') WITHIN GROUP (ORDER BY b.bldgcode) AS Bldgs
FROM buildings b, sites s
WHERE b.sitecode = s.sitecode
GROUP BY s.sitedesc

然而，GROUP BY子句在xml“not by group by expression”中引发错误（我原以为但似乎无法修复）。下面的示例，是否可以在XMLELEMENT中使用LISTAGG？

SELECT XMLELEMENT("rss", 
            XMLATTRIBUTES('http://www.georss.org/georss' AS "xmlns:georss"),
                    XMLELEMENT("channel",
                                 XMLAGG(XMLELEMENT("item",
                                                   XMLFOREST(title AS "title",
                                                              description AS "description",
                                                              point AS "georss:point"))))).EXTRACT('/*')
    FROM (SELECT trim(s.sitedesc) AS title, 
          'Employee Count: ' || s.sitefte || '. Bldg Gross SF: ' || s.bldgarea || '. ' || CASE WHEN s.leasestat = '0' THEN 'Owned' WHEN s.leasestat = '1' THEN 'Leased, end date: ' || trim(l.edate) END || LISTAGG(trim(b.bldgcode)||' '||trim(b.bldgdesc), ', ') WITHIN GROUP (ORDER BY b.bldgcode) AS description, 
          trim(s.latitude) || ' ' || trim(s.longitude) AS point
          FROM site s, lease l, buildings b
          WHERE s.sold <> 1
            AND s.longitude != ' '
            AND s.sitecode = l.sitecode
            AND b.sitecode = s.sitecode
          GROUP BY s.sitedesc
        )

所需的XML示例

<rss xmlns:georss="http://www.georss.org/georss">
<channel>
    <item>
        <title>SITE DESCRIPTION</title>
        <description>Employee Count: ###. Bldg Gross SF: ####. Owned/Leased Building1, building2, etc.</description>
        <georss:point>LAT LON</georss:point>
    </item>
....
</channel>
</rss>

Answer 1

改变你的小组。

select xmlelement("rss", xmlattributes('http://www.georss.org/georss' as "xmlns:georss"), xmlelement("channel", xmlagg(xmlelement("item", xmlforest(title as "title", description as "description", point as "georss:point")))))
       .extract('/*')
  from (select trim(s.sitedesc) as title,
                'Employee Count: ' || s.sitefte || '. Bldg Gross SF: ' || s.bldgarea || '. ' || case
                  when s.leasestat = '0' then
                   'Owned'
                  when s.leasestat = '1' then
                   'Leased, end date: ' || trim(l.edate)
                end || listagg(trim(b.bldgcode) || ' ' || trim(b.bldgdesc), ', ') within group(order by b.bldgcode) as description,
                trim(s.latitude) || ' ' || trim(s.longitude) as point
           from site s, lease l, buildings b
          where s.sold <> 1
            and s.longitude != ' '
            and s.sitecode = l.sitecode
            and b.sitecode = s.sitecode
          group by s.sitedesc, s.sitefte, s.bldgarea, s.leasestat, l.edate, s.latitude, s.longitude)

这应该可以正常工作。

在XMLELEMENT XMLFOREST中使用LISTAGG

1 个答案: