Question

我有一个格式为0018103AB839的mac地址，我希望将其显示为：00:18:10:3A:B8:39

我正在尝试使用string.Format执行此操作，但我无法找到确切的语法。

现在我正在尝试这样的事情：

    string macaddress = 0018103AB839;
    string newformat = string.Format("{0:00:00:00:00:00:00}", macaddress);

这甚至可能吗？或者我应该使用string.Insert？

Answer 1

重新格式化字符串以将其显示为MAC地址：

var macadres = "0018103AB839";

var regex = "(.{2})(.{2})(.{2})(.{2})(.{2})(.{2})";
var replace = "$1:$2:$3:$4:$5:$6";
var newformat = Regex.Replace(macadres, regex, replace);    

// newformat = "00:18:10:3A:B8:39"

如果要验证输入字符串，请使用此正则表达式（感谢J0HN）：

var regex = String.Concat(Enumerable.Repeat("([a-fA-F0-9]{2})", 6));

Answer 2

string input = "0018103AB839";

var output = string.Join(":", Enumerable.Range(0, 6)
    .Select(i => input.Substring(i * 2, 2)));

Answer 3

var strings = macadres
    .Select((value, index) => new { Pair = index / 2, value })
    .GroupBy(g => g.Pair )
    .Select(g => g.Aggregate("", (accumulated, elem) => accumulated+elem.value));

string formatted = String.Join(":", strings);

Answer 4

假设我们将Mac地址存储在long中。这是如何在格式化的字符串中使用它：

ulong lMacAddr = 0x0018103AB839L;
string strMacAddr = String.Format("{0:X2}:{1:X2}:{2:X2}:{3:X2}:{4:X2}:{5:X2}",
    (lMacAddr >> (8 * 5)) & 0xff, 
    (lMacAddr >> (8 * 4)) & 0xff,
    (lMacAddr >> (8 * 3)) & 0xff,
    (lMacAddr >> (8 * 2)) & 0xff,
    (lMacAddr >> (8 * 1)) & 0xff,
    (lMacAddr >> (8 * 0)) & 0xff);

使用c＃中的string.Format格式化MAC地址

4 个答案: