警报对话框在用户看到任何内容之前消失

Question

@Override
    public void onBackPressed() {
    // TODO Auto-generated method stub            
      PopIt("Exit Application", "Are you sure you want to exit?");

        super.onBackPressed();

    }

    public void PopIt( String title, String message ){
            new AlertDialog.Builder(this)
            .setTitle( title )
            .setMessage( message )
            .setPositiveButton("YES", new OnClickListener() 
            {
                public void onClick(DialogInterface arg0, int arg1) {
                    //do stuff onclick of YES
                    finish();
                }
            }).setNegativeButton("NO", new OnClickListener() {
                public void onClick(DialogInterface arg0, int arg1) {
                    //do stuff onclick of CANCEL
                    Toast.makeText(getBaseContext(), "You touched CANCEL", Toast.LENGTH_SHORT).show();
                }
            }).show();
        }

此警报对话框速度太快，因为我无法阅读或点击它！为什么会这样？

Answer 1

问题是你在调用super.onBackPressed（）之前抛出Popit; 删除它：）

Answer 2

super.onBackPressed();

删除此行。

如果您不删除它，将触发默认功能，这将关闭当前活动。

Answer 3

试试这个

 public void onBackPressed() {
    // TODO Auto-generated method stub     

 super.onBackPressed();       
      PopIt("Exit Application", "Are you sure you want to exit?");



    }

Answer 4

试试这个

@Override
public void onBackPressed() {
new AlertDialog.Builder(this)
    .setTitle("Really Exit?")
    .setMessage("Are you sure you want to exit?")
    .setNegativeButton(android.R.string.no, null)
    .setPositiveButton(android.R.string.yes, new OnClickListener() {

        public void onClick(DialogInterface arg0, int arg1) {
            youractivity.super.onBackPressed();
        }
    }).create().show();
}

Answer 5

删除此行super.onBackPressed();

您正在onBackPressed（）

中显示对话框

所以它就像你的onBackPressed（）;

的首要行为

所以不要调用超类方法。

Answer 6

删除super.onBackPressed();

这将有效：

public void onBackPressed() {
    // TODO Auto-generated method stub          
      PopIt("Exit Application", "Are you sure you want to exit?");
    }