Question

我正在尝试使用类别中供应商的结果显示矩阵表。像：

+-----------+-------------+-------------+------+
|           | Category 1  | Category 2  | ...  |
+-----------+-------------+-------------+------+
| Vendor 1  |       8900  |          0  | ...  |
| Vendor 2  |      56890  |       4000  | ...  |
|      ...  |        ...  |        ...  | ...  |
+-----------+-------------+-------------+------+

我已经只针对一家供应商进行了查询：

SELECT ut.unit_name, IFNULL(SUM(commission_fix_out),0)
FROM transaction t
JOIN office_per_transaction opt
ON t.id = opt.transaction_id
JOIN_vendor_per_transaction ppt
ON t.id = ppt.transaction_id
AND ppt.vendor_id = 2
RIGHT JOIN unit_type ut
ON t.unit_type_id = ut.id
AND transaction_end_week BETWEEN 0 AND 14
AND YEAR(transaction_end_date) = 2012
GROUP BY ut.id

这给了我以下结果：

+-------------+---------+
| Category    | Result  |
+-------------+---------+
| Category 1  |  56890  |
| Category 2  |   4000  |
|        ...  |    ...  |
+-------------+---------+

现在，我希望在给定的办公室中看到每个供应商的此查询的串联。

首先，我尝试用AND ppt.vendor_id = 2替换AND ppt.vendor_id IN (SELECT id FROM vendor WHERE office_id = 1)，但这给了我办公室中所有供应商的总结果。

其次，我尝试使用子查询。但这给了我一个错误，说明未知列。

我想要达到的结果是：

+-----------+--------- -------+
| Vendor    | Results         |
+-----------+-----------------+
| Vendor 1  | 8900,0,...      |
| Vendor 2  | 56890,4000,...  |
| ...       | ...,...,...     |
+-----------+-----------------+

我是在尝试一些不切实际的东西，我是否应该为每个供应商执行上述查询。或者我在这里错过了什么？

@SashiKant我上次尝试了很多查询，但是它是这样的：

SELECT v.id, GROUP_CONCAT(r.result) FROM vendor v, ( SELECT ut.unit_name, IFNULL(SUM(commission_fix_out),0) as result FROM transaction t JOIN office_per_transaction opt ON t.id = opt.transaction_id JOIN vendor_per_transaction ppt ON t.id = ppt.transaction_id AND ppt.vendor_id = p.id RIGHT JOIN unit_type ut ON unit_type_id = ut.id AND transaction_end_week BETWEEN 0 AND 14 AND YEAR(transaction_end_date) = 2012 GROUP BY ut.id) as r

Answer 1

您可能需要加入vendor表以获得所需的供应商（而不是单个供应商）。你还需要在GROUP BY中使用更多的子句（你真的应该使用GROUP BY子句中SELECT的所有非聚合列 - mysql不反对，但是如果你错过了一些，那么大多数SQL会反对。）

这样的事情（没有经过测试，请原谅任何错别字）

SELECT vendor_id, ut.id, ut.unit_name, IFNULL(SUM(commission_fix_out),0)
FROM transaction t
INNER JOIN office_per_transaction opt
ON t.id = opt.transaction_id
INNER JOIN_vendor_per_transaction ppt
ON t.id = ppt.transaction_id
INNER JOIN vendor ve
ON ve.id = ppt.vendor_id 
RIGHT JOIN unit_type ut
ON t.unit_type_id = ut.id
AND transaction_end_week BETWEEN 0 AND 14
AND YEAR(transaction_end_date) = 2012
WHERE ve.office_id = 1
GROUP BY vendor_id, ut.id, ut.unit_name
ORDER BY vendor_id, ut.id, ut.unit_name

如果您希望每个供应商的一行包含该列供应商的所有金额的单一列，那么就像这样。

SELECT vendor_id, GROUP_CONCAT(CommisionAmount)
FROM (
SELECT vendor_id, ut.id, ut.unit_name, IFNULL(SUM(commission_fix_out),0) AS CommisionAmount
FROM transaction t
INNER JOIN office_per_transaction opt
ON t.id = opt.transaction_id
INNER JOIN_vendor_per_transaction ppt
ON t.id = ppt.transaction_id
INNER JOIN vendor ve
ON ve.id = ppt.vendor_id 
RIGHT JOIN unit_type ut
ON t.unit_type_id = ut.id
AND transaction_end_week BETWEEN 0 AND 14
AND YEAR(transaction_end_date) = 2012
WHERE ve.office_id = 1
GROUP BY vendor_id, ut.id, ut.unit_name
ORDER BY vendor_id, ut.id, ut.unit_name) Sub1

Answer 2

您可以使用group_concat。

伪SQL：

select vendor, group_concat(result)
from mytable
group by vendor

您可以通过创建视图来“简化”它。由于我不知道你的表结构，这只是猜测

create view commissions as
    SELECT ppt.vendor_id as vendor, ut.unit_name as category,
           IFNULL(SUM(commission_fix_out),0) as commission
    FROM transaction t
    JOIN office_per_transaction opt
    ON t.id = opt.transaction_id
    JOIN_vendor_per_transaction ppt
    ON t.id = ppt.transaction_id
    RIGHT JOIN unit_type ut
    ON t.unit_type_id = ut.id
    AND transaction_end_week BETWEEN 0 AND 14
    AND YEAR(transaction_end_date) = 2012
    GROUP BY ppt.vendor_id, ut.id;

然后选择

select vendor, group_concat(commission)
from commissions
group by vendor;

每行Mysql子查询

2 个答案: