Question

我正试图点击一个按钮移动一个子视图但它崩溃并给我-[MainGameDisplay openTimeChanger:]: unrecognized selector sent to instance 0x10e443d0

这就是我正在做的事情：

@interface:
UIImageView *changerBackground;
@implementation

timerView = [[UIView alloc] initWithFrame:CGRectMake(0, 278, 105, 27)];
[self.view addSubview:timerView];

changerBackground = [[UIImageView alloc] init];
[changerBackground setImage:[UIImage imageNamed:@"speedbackground.png"]];
changerBackground.frame = CGRectMake(-12 , 9, 105, 33);
[changerBackground setUserInteractionEnabled:YES];
[timerView addSubview:changerBackground];

UIButton *timerBackground = [UIButton buttonWithType:UIButtonTypeCustom];
[timerBackground setBackgroundImage:[UIImage imageNamed:@"Time Background.png"] forState:UIControlStateNormal];
[timerBackground setBackgroundImage:[UIImage imageNamed:@"Time Background.png"] forState:UIControlStateHighlighted];
[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside];
timerBackground.frame = CGRectMake(-2 , 15, 102, 27);
[timerView addSubview:timerBackground];



-(void)openTimeChanger {
    [UIView animateWithDuration:0.2f
                     animations:^{
                         changerBackground.frame = CGRectMake(-12 , -16, 105, 33);
                     }
                     completion:Nil];
}

还要注意，changerBackground有3个子视图。

Answer 1

您需要更改此内容，

[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside];

到

[timerBackground addTarget:self action:@selector(openTimeChanger) forControlEvents:UIControlEventTouchUpInside]; //note that semicolon is not there in the method name

您的方法定义为-(void)openTimeChanger而非-(void)openTimeChanger:(id)sender。它试图找到一个具有这个定义的方法，但同样的方法不可用，因此崩溃。

如果您要使用[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside];，请将方法更改为-(void)openTimeChanger:(id)sender。

使用CGRectMake移动子视图会导致崩溃

1 个答案: