我正在使用jquery / ajax提交表单而不刷新页面。
这是我的表单代码:
<div id="event_form">
<form name="event_submit" method="post" action="">
<label for="what" id="what_label">What is the event?</label>
<input type="text" name="what" id="what" class="entry_field" />
<br />
<label class="error" for="what" id="what_error">This field is required.</label>
<br />
<label for="where" id="where_label">Where is the event?</label>
<input type="text" name="where" id="where" class="entry_field" />
<br />
<label class="error" for="where" id="where_error">This field is required.</label>
<br />
<label for="when" id="when_label">When is the event?</label>
<input type="text" name="when" id="when" class="entry_field" />
<br />
<label class="error" for="when" id="when_error">This field is required.</label>
<br />
<label for="details" id="details_label">Additional details</label>
<textarea rows="8" cols="30" name="details"></textarea>
<br />
<input type="submit" value="Post Event" name="submit" class="submitButton" title="Click to post event" />
</form>
</div>
这是我的jquery / ajax:
$(function() {
$('.error').hide();
$(".submitButton").click(function() {
// validate and process form
// first hide any error messages
$('.error').hide();
var what = $("input#what").val();
if (what == "") {
$("label#what_error").show();
$("input#what").focus();
return false;
}
var where = $("input#where").val();
if (where == "") {
$("label#where_error").show();
$("input#where").focus();
return false;
}
var when = $("input#when").val();
if (when == "") {
$("label#when_error").show();
$("input#when").focus();
return false;
}
var dataString = 'what='+ what + '&where=' + where + '&when=' + when;
//alert (dataString);return false;
$.ajax({
type: "POST",
url: "event_submit.php",
data: dataString,
success: function() {
$('#event_form').html("<div id='message'></div>");
$('#message').html("<h2>Event Submitted!</h2>");
}
});
return false;
});
});
这是php:
<?php
include "conf.php";
if ((isset($_POST['what'])) && (strlen(trim($_POST['what'])) > 0)) {
$what = stripslashes(strip_tags($_POST['what']));
} else {$what = 'No description of the event entered.';}
if ((isset($_POST['where'])) && (strlen(trim($_POST['where'])) > 0)) {
$where = stripslashes(strip_tags($_POST['where']));
} else {$where = 'No location entered for the event.';}
if ((isset($_POST['when'])) && (strlen(trim($_POST['when'])) > 0)) {
$when = stripslashes(strip_tags($_POST['when']));
} else {$when = 'No time entered for the event.';}
if ((isset($_POST['details'])) && (strlen(trim($_POST['details'])) > 0)) {
$details = stripslashes(strip_tags($_POST['details']));
}
if(isset($details)){
mysql_query("INSERT INTO `events` (`school_id`, `what`, `where`, `when`, `details`) VALUES ('$school_id', '$what', '$where', '$when', '$details')") or die(mysql_error());
}
else {
mysql_query("INSERT INTO `events` (`school_id`, `what`, `where`, `when`) VALUES ('$school_id', '$what', '$where', '$when')") or die(mysql_error());
}
exit;
?>
在表单所在的页面上,网址中提供的“$ school_id”为“school = 1687”或其他。我可以使用$ _GET在表单页面上检索它,但是如何将此变量传递给ajax / php?我需要将它作为变量插入表中。
答案 0 :(得分:1)
像
这样的东西<input type="hidden" name="schoolid" value="<?php echo $_GET['school_id']; ?>">
在你的表格中? 请理解,回应未经过简化的GET参数仅用于说明目的 - 它让您对CSS大加开放!
答案 1 :(得分:0)
您可以使用隐藏的输入。类似的东西:
<input type="hidden" id="school_id" value="<?php echo $school_id" />
然后将其添加到您的数据变量中:
var dataString = 'school_id='+$('#school_id').val()+'&what='+ what + '&where=' + where + '&when=' + when;
然后在你的php页面上检索它:
$school_id = $_POST['school_id'];
答案 2 :(得分:0)
尝试:
//Retrieving $_GET['school_id'] and passing as JSON object
var school_id = <?php echo $_GET['school_id']; ?>
var dataString = { 'what': what, 'where' : where, 'when': when, 'school_id': school_id }
$.ajax({
type: "POST",
url: "event_submit.php",
data: dataString,
type: json,
success: function() {
$('#event_form').html("<div id='message'></div>");
$('#message').html("<h2>Event Submitted!</h2>");
}
});
您可以$_POST['school_id']
上的event_submit.php
访问它。
答案 3 :(得分:0)
在表单中添加隐藏字段,如下所示
<input type="hidden" id="school_id" value="<?php echo $_REQUEST['school']; ?>" />
现在在jQuery脚本中,您可以通过单行代码
简单地获取所有表单元素值var dataString = $('#form-id-here').serialize();
然后通过ajax发送它
$.ajax({
type: "POST",
url: "event_submit.php",
data: dataString,
success: function() {
$('#event_form').html("<div id='message'></div>");
$('#message').html("<h2>Event Submitted!</h2>");
}
});
最后将mysql插入查询更改为followig
mysql_query("INSERT INTO `events` (`school_id`, `what`, `where`, `when`, `details`) VALUES ('".$_POST['school_id']."', '$what', '$where', '$when', '$details')") or die(mysql_error());
我想现在你已经拥有了所有需要的东西。享受:)