查询:
SELECT nummer
FROM tabell_med_nummer
WHERE SUBSTR(nummer, -1) = 0
此查询选择表tabell_med_nummer中以“0”结尾的数字。例如,它将选择1000,1010,1020,但不选择1001,1002等。
我需要根据这个得到一个范围。例如1000-1100或1010-1023。范围的大小是可变的。它的结尾并不重要,但它必须选择一个以“0”结尾的数字,如1010。
棘手的部分是表中不存在每个数字。因此,如果表格中不存在1004,那么我需要100的范围,它不能从1000开始。
有谁知道如何解决这个问题?
根据要求:
+----+-------------+-------+-------+-------------------------------+---------------+---------+------+------+---------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+-------+-------------------------------+---------------+---------+------+------+---------------------------------+
| 1 | SIMPLE | f | ALL | NULL | NULL | NULL | NULL | 19 | Using temporary; Using filesort |
| 1 | SIMPLE | t2 | index | telefonnummer,telefonnummer_2 | telefonnummer | 5 | NULL | 1001 | Using index; Using join buffer |
| 1 | SIMPLE | p | ALL | NULL | NULL | NULL | NULL | 4568 | Using where; Using join buffer |
| 1 | SIMPLE | t3 | index | telefonnummer,telefonnummer_2 | telefonnummer | 5 | NULL | 1001 | Using index; Using join buffer |
| 1 | SIMPLE | t1 | ALL | telefonnummer,telefonnummer_2 | NULL | NULL | NULL | 1001 | Using where; Using join buffer |
+----+-------------+-------+-------+-------------------------------+---------------+---------+------+------+---------------------------------+
5 rows in set (0.00 sec)
我更改了一些表和字段名称,并添加了一些连接和法规:
SELECT t1.telefonnummer start, t2.telefonnummer end, t1.kundenummer kundenummer, t1.fornavn fornavn, t1.etternavn etternavn, t1.bedriftsnavn bedriftsnavn, t1.organisasjonsnummer organisasjonsnummer, t1.partnerID partnerID
FROM TELEFONNUMMERTILDELING t1
JOIN TELEFONNUMMERTILDELING t2
ON t1.telefonnummer % 10 = 0
AND t1.telefonnummer <= t2.telefonnummer
JOIN TELEFONNUMMERTILDELING t3
ON t3.telefonnummer BETWEEN t1.telefonnummer AND t2.telefonnummer
JOIN TELEFONNUMMERTILDELING_POSTNUMMER p
ON p.postnummer = 4085
JOIN TELEFONNUMMERTILDELING_FYLKE f
ON f.ID = p.fylkeID GROUP BY start, end
HAVING end - start + 1 = COUNT(*)
AND end - start + 1 = 50
AND (kundenummer IS NULL OR kundenummer = '')
AND (fornavn IS NULL OR fornavn = '')
AND (etternavn IS NULL OR etternavn = '')
AND (bedriftsnavn IS NULL OR bedriftsnavn = '')
AND (organisasjonsnummer IS NULL OR organisasjonsnummer = '')
AND partnerID = 1001
答案 0 :(得分:2)
-- get the start and end points
SELECT t1.nummer AS start, t2.nummer AS end
-- pair every possible start number with every potential end number
FROM tabell_med_nummer t1
JOIN tabell_med_nummer t2
ON t1.nummer % 10 = 0 AND t1.nummer <= t2.nummer
-- obtain every number in between
JOIN tabell_med_nummer t3
ON t3.nummer BETWEEN t1.nummer AND t2.nummer
-- group into potential ranges
GROUP BY start, end
-- now limit only to contiguous ranges
HAVING end - start + 1 = COUNT(*)
-- and those that contain the desired number of records
AND end - start + 1 = ?
如果nummer
不能保证唯一,例如如果使用UNIQUE
约束,则需要将COUNT(*)
替换为性能较低的COUNT(DISTINCT t3.nummer)
,否则将t3
替换为(SELECT DISTINCT nummer FROM tabell_med_nummer)
。
答案 1 :(得分:1)
在WHERE
子句中添加其他条件。
SELECT nummer
FROM tabell_med_nummer
WHERE SUBSTR(nummer, -1) = 0 AND
nummer BETWEEN 1000 AND 1100