我拍摄了一个Bitmap图像并从中拉出了R，G，B整数，用于指定的像素行。将int转换为字符串，以便我可以打印我的6种特定颜色。我无法弄清楚如何使用int。
问题 我能够将0-184行（对应于该行中的像素）打印为顺序数据1234 ...或者颜色为红色，红色，红色，黑色，黑色，灰色....
然而，我需要计算相同颜色，显示相似颜色的总和，并重置计数器，直到颜色再次出现然后重新计数。我认为if或if else会这样做但不完全。可能是我的代码结构导致了问题？
所以我想要的是：
5 red,
10 black,
2 red,
1 gray,
等......
这是我的代码，我是初学者，所以批评我缺乏知识，以便我可以正确学习。
#include <iostream>
#include <sstream>
#include <string>
#include "EasyBMP.h"
#include "EasyBMP_BMP.h"
#include "EasyBMP_DataStructures.h"
#include "EasyBMP_VariousBMPutilities.h"
//Conversion and comparison function
void calculate(int i, int x, int p);
int main(int argc, const char * argv[])
{
BMP Image;
Image.ReadFromFile( "BMP GOES HERE 24bit" );
std::cout << "Image Height and Width: " << Image.TellHeight() << " x " << Image.TellWidth() << std::endl;
std::cout << "Enter your row: ";
int pixX = 0;
std::cin >> pixX;
//Set getpixel to top of row
int pixY = 0;
for( pixY = 0; pixY < Image.TellHeight() ; pixY++ )
{
std::cout << "Pixel: " << pixY + 1;
RGBApixel Temp = Image.GetPixel(pixX,pixY);
//Array to store pixel color ints
int pixy[3];
pixy[0] = Temp.Red;
pixy[1] = Temp.Green;
pixy[2] = Temp.Blue;
calculate(pixy[0], pixy[1], pixy[2]);
}
return 0;
}
void calculate(int rnum, int gnum, int bnum)
{
//String which will contain the result
std::string result;
//Stream used for the conversion
std::ostringstream convert;
//Insert the textual representation of 'Number' in the characters in the stream
convert << rnum;
convert << gnum;
convert << bnum;
// set 'Result' to the contents of the stream
result = convert.str();
// compare result to my given value
if (result == "25500")
{
std::cout << " RED " << std::endl;
}
if (result == "255255255")
{
std::cout << " WHITE " << std::endl;
}
if (result == "000")
{
std::cout << " BLACK" << std::endl;
}
if (result == "148148148")
{
std::cout << " GRAY " << std::endl;
}
if (result == "267326")
{
std::cout << " GREEN " << std::endl;
}
if (result == "2551260")
{
std::cout << " ORANGE " << std::endl;
}
}
以下是工作代码。请注意，如果您使用它，我的图像只有6种特定颜色。要更改打印输出，必须根据需要修改switch语句。
#include <iostream>
#include <vector>
#include "EasyBMP.h"
#include "EasyBMP_BMP.h"
#include "EasyBMP_DataStructures.h"
#include "EasyBMP_VariousBMPutilities.h"
long toRGB(long red, long grn, long blu);
int main(int argc, const char * argv[])
{
BMP Image;
Image.ReadFromFile( "Your BMP HERE" );
std::cout << "Image Height and Width: " << Image.TellHeight() << " x " << Image.TellWidth() << std::endl;
std::cout << "Enter your row: ";
int pixX = 0;
std::cin >> pixX;
if (pixX != 0) //Subtract one from input if not 0, image starts at 0,0
{
pixX -= 1;
}
long pop = 0;
long pop1 = 0;
RGBApixel current = Image.GetPixel(pixX,0);
long pixy1[3]; //Array to store pixel color ints
pixy1[0] = current.Red;
pixy1[1] = current.Green;
pixy1[2] = current.Blue;
pop1 = toRGB(pixy1[0], pixy1[1], pixy1[2]);
int count = 0;
for( int pixY = 0; pixY < Image.TellHeight() ; pixY++ )
{
RGBApixel Temp = Image.GetPixel(pixX,pixY);
long pixy[3]; //Array to store pixel color ints
pixy[0] = Temp.Red;
pixy[1] = Temp.Green;
pixy[2] = Temp.Blue;
pop = toRGB(pixy[0], pixy[1], pixy[2]);
if (pop == pop1)
{
count++;
}
else
{
switch (pop1) {
case 0:
std::cout << "(" << count << ")\t" << "BLACK\n" << std::endl;
break;
case 16711680:
std::cout << "(" << count << ")\t" << "RED\n" << std::endl;
break;
case 9737364:
std::cout << "(" << count << ")\t" << "GRAY\n" << std::endl;
break;
case 16777215:
std::cout << "(" << count << ")\t" << "WHITE\n" << std::endl;
break;
case 1722650:
std::cout << "(" << count << ")\t" << "GREEN\n" << std::endl;
break;
case 16743936:
std::cout << "(" << count << ")\t" << "ORANGE\n" << std::endl;
break;
default:
std::cout << " !!!NO Specified COLOR For!!! " << pop1 << std::endl;
break;
}
pop1 = pop; //Reset the count and current color
count = 1;
}
}
if (count > 0) //Returns last color and count
{
switch (pop1) {
case 0:
std::cout << "(" << count << ")\t" << "BLACK\n" << std::endl;
break;
case 16711680:
std::cout << "(" << count << ")\t" << "RED\n" << std::endl;
break;
case 9737364:
std::cout << "(" << count << ")\t" << "GRAY\n" << std::endl;
break;
case 16777215:
std::cout << "(" << count << ")\t" << "WHITE\n" << std::endl;
break;
case 1722650:
std::cout << "(" << count << ")\t" << "GREEN\n" << std::endl;
break;
case 16743936:
std::cout << "(" << count << ")\t" << "ORANGE\n" << std::endl;
break;
default:
std::cout << " !!!NO Specified COLOR For!!! " << pop1 << std::endl;
break;
}
}
return 0;
}
long toRGB(long a, long b, long c) //Function to convert R, G, B values to unique value
{
long color = 0;
color |= (a & 255) << 16;
color |= (b & 255) << 8;
color |= (c & 255);
return color;
}
答案 0 :(得分：0)
您可以通过许多不同的方法来计算给定颜色的像素数。如果您感兴趣的颜色列表相当短，则可以创建一个大小等于初始化为全0的颜色数的数组，然后编写一个函数，根据传递给该颜色的颜色返回该数组的索引。它（例如红色= 0，白色= 1，任意顺序;常量可能是跟踪它的好方法），然后循环调用每个像素上的函数并在给定索引处递增数组。
这很简单但非常不优雅。
答案 1 :(得分：0)
我之前没有真正理解你的问题，所以我写了一个更适合你所问的新答案。
我认为你可以用这样的东西得到你想要的东西（修改你的代码）：
RGBApixel current = Image.GetPixel(pixX,0);
int count = 0;
for( pixY = 0; pixY < Image.TellHeight() ; pixY++ )
{
RGBApixel Temp = Image.GetPixel(pixX,pixY);
if (Temp == current)
{
count++;
}
else
{
// same-color sequence ended
// Add code here to print out current color and count
--- your output code ----
// now reset the count and current color
current = Temp;
count = 1;
}
}
// Now just print out the last sequence
if (count > 0)
{
--- your output code here again ---
}
我不确定的一件事是，如果有的话，是为RGBApixel定义了==运算符。如果没有定义或者似乎没有基于颜色等同像素，只需编写像pixelsAreEqual(RBGApixel p1, RGBApixel p2)这样的函数，它需要两个像素，如果它们具有相同的RGB值，则返回true。