我正在使用带有DataTemplate的ListBox。
<ListBox Grid.Row="1" Grid.ColumnSpan="3" Grid.RowSpan="3" HorizontalAlignment="Stretch" VerticalAlignment="Stretch"
ItemsSource="{Binding Order.OrderLines}" >
<ListBox.ItemTemplate>
<DataTemplate>
<Grid>
<Grid.RowDefinitions>
<RowDefinition />
<RowDefinition />
<RowDefinition />
</Grid.RowDefinitions>
<Grid.ColumnDefinitions>
<ColumnDefinition />
<ColumnDefinition />
</Grid.ColumnDefinitions>
<TextBlock Grid.Column="0">Qty</TextBlock>
<TextBox Text="{Binding LineQty, Mode=TwoWay}" Grid.Column="1" />
<TextBlock Grid.Row="1" Grid.Column="0">Weight</TextBlock>
<TextBox Text="{Binding Path=LineWeight}" Grid.Row="1" Grid.Column="1" />
<TextBlock Grid.Column="0" Grid.Row="2">Pallet Weights</TextBlock>
<TextBox Text="{Binding PalletWeights}" Grid.Row="2" Grid.Column="1" />
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
TextBox值正确绑定。问题是我的ViewModel上有一个名为“ViewMode”的属性,我将TextBox的IsEnabled属性绑定到App.xaml Style DataTrigger:
<Style TargetType="{x:Type TextBox}">
<Style.Triggers>
<DataTrigger Binding="{Binding ViewMode}" Value="Add">
<Setter Property="BorderBrush" Value="White"></Setter>
<Setter Property="BorderThickness" Value="2,2,0,0"></Setter>
<Setter Property="BorderBrush" Value="Black"></Setter>
<Setter Property="BorderThickness" Value="0,0,2,2"></Setter>
<Setter Property="Background" Value="LightBlue"></Setter>
<Setter Property="Foreground" Value="Black"></Setter>
<Setter Property="FontWeight" Value="Bold"></Setter>
<Setter Property="IsEnabled" Value="true"></Setter>
</DataTrigger>
<DataTrigger Binding="{Binding ViewMode}" Value="Edit">
<Setter Property="BorderBrush" Value="White"></Setter>
<Setter Property="BorderThickness" Value="2,2,0,0"></Setter>
<Setter Property="BorderBrush" Value="Black"></Setter>
<Setter Property="BorderThickness" Value="0,0,2,2"></Setter>
<Setter Property="Background" Value="LightBlue"></Setter>
<Setter Property="Foreground" Value="Black"></Setter>
<Setter Property="FontWeight" Value="Bold"></Setter>
<Setter Property="IsEnabled" Value="true"></Setter>
</DataTrigger>
<DataTrigger Binding="{Binding ViewMode}" Value="View">
<Setter Property="IsEnabled" Value="false"></Setter>
<Setter Property="Foreground" Value="Gray"></Setter>
</DataTrigger>
</Style.Triggers>
<Setter Property="Margin" Value="2" />
</Style>
这适用于我的所有其他TextBox。如何从DataTemplate中获取IsEnabled属性? ListBox的DataContext引用了ViewModel属性“Order”,所以我认为它应该能够看到ViewModel属性“ViewMode”。
谢谢, -sid。
答案 0 :(得分:1)
在DataTemplate中,您无法直接从ViewModel访问属性(您不会'继承'DataContext)。 假设您的ViewModel是整个视图的DataContext,您可以创建一个代理:
class BindingProxy : Freezable
{
#region Freezable Members
protected override Freezable CreateInstanceCore()
{
return new BindingProxy();
}
#endregion
/// <summary>
/// Saves the DataContext from the whole view
/// </summary>
public object DataContext
{
get { return (object)GetValue(DataContextProperty); }
set { SetValue(DataContextProperty, value); }
}
public static readonly DependencyProperty DataContextProperty =
DependencyProperty.Register("DataContext", typeof(object), typeof(BindingProxy), new UIPropertyMetadata(null));
}
然后,在您的XAML文件中,您需要引用BindingProxy所在的命名空间:
<UserControl xmlns:utilities="clr-namespace:MyApp.NamespaceWhereBindingProxyIsLocated"
...
稍后,您为视图创建一个BindingProxy实例,并将其与视图的DataContext链接(请注意DataContext = {Binding}部分):
<UserControl.Resources>
<utilities:BindingProxy x:Key="proxy" DataContext="{Binding}"/>
</UserControl.Resources>
最后,您可以将它用作每个TextBox的DataContext:
<ListBox.ItemTemplate>
<DataTemplate>
<Grid>
..
<TextBox Text="{Binding Path={TemplateBinding DataContext.LineQty}, Mode=TwoWay}" DataContext="{Binding Source={StaticResource proxy}, Path=DataContext}"/>
..
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
希望有所帮助
答案 1 :(得分:1)
您需要在Binding中使用RelativeSource
标记扩展名,以防您想要像这样前往Visual Tree -
<DataTrigger Binding="{Binding DataContext.ViewMode,
RelativeSource={RelativeSource FindAncestor,
AncestorType = UserControl}}"
Value="Add">
</DataTrigger>
默认DataContext
TextBox
将object of OrderLine
LineQty
您的财产ViewMode
所在的位置。因此,样式在OrderLine
的对象而不是ViewModel中搜索DataContext
属性,因此您需要使用RelativeSource明确要求它在您的UserControl的ViewModel
中搜索它。你的{{1}}。