Question

我正在尝试以星星和半星的形式创建1到5（包括.5值）的用户评级的直观表示。我已经从MySQL数据库创建了用户评级数组，我已经平均这些值以创建数字形式的平均用户评级。我想做的就是拿这个值..

$averageuserrating

如果该值为“1”，则返回此代码一次

 echo '<img src="images/star.png" class="ratingstar" />';

如果$ averageuserrating为1.5，则返回此代码

<img src="images/star.png" class="ratingstar" /><img src="images/halfstar.png" class="ratingstar" />

等等......如果没有10个嵌套的if语句，有没有办法做到这一点？

Answer 1

可以通过以下方式完成：

$fullStar = '<img src="images/star.png" class="ratingstar" />';
$halfStar = '<img src="images/halfstar.png" class="ratingstar" />';

$rating = 1.5;

while($rating > 0){
    if($rating >= 1){
        echo $fullStar;
        $rating = $rating - 1;
        continue;
    }

    if($rating >= 0.5){
        echo $halfStar;
        $rating = $rating - 0.5;
    }
}

另一方面，这不是显示评级系统的最佳方式。

Answer 2

for($i = 1; $i <= floor($averageuserrating); $i++)
    echo '<img src="images/star.png" class="ratingstar" />';
if($averageuserrating > floor($averageuserrating))
    echo '<img src="images/halfstar.png" class="ratingstar" />';

注意：如果平均值不仅增加0.5，而且例如你可以得到1.4：将第二个条件更改为：

if($averageuserrating >= (floor($averageuserrating) + 0.5))

Answer 3

只需使用str_repeat函数和一点数学。

$full_star = '<img src="images/star.png" class="ratingstar" />';
$half_star = '<img src="images/halfstar.png" class="ratingstar" />';

echo str_repeat( $full_star, floor($averageuserrating) );
if(! is_int($averageuserrating) ){
    echo $half_star;
}

我认为它会正常工作。

Answer 4

您可以使用switch语句。

switch($value){
case "1";
echo '<img src="images/star1.png" class="ratingstar" />';
break; 
case "1";
echo '<img src="images/star2.png" class="ratingstar" />';
break;

so on and so forth.. 

}

Answer 5

以下是可能解决方案的代码：

$numWholeStars = (int)$averageuserrating;

$numHalfStars = $averageuserrating - (int)$averageuserrating;

for($i = 0; $i < $numWholeStars; $i++) {
    echo '<img src="images/star.png" class="ratingstar" />';
}

if($numHalfStars != 0) {
    echo '<img src="images/halfstar.png" class="ratingstar" />';
}

Answer 6

听起来你需要重新调整基础代码的因素a）收集所有评级b）显示评级应显示的星数。首先看php math - modulus

get_user_ratings($user="bob")
{
    15 - the user ratings should/could be in 1 place (int)users.total_ratings
    // lets say there are 15 records similar to the one below
    jim, 1, bob 
    ...
    mary, 1.5, bob

    // calculate the average of all votes
    ...
    ...
    /* If your rating system offers the chance to rate a user 1.5 stars
     use modulus to check if the rating needs half stars */
    $stars = "";
    if( $averageuserrating % 1 == 0)
    {
        for(
            i=0;
            i<$averageuserrating-1; 
           $i++;$stars .= '<img src="images/star.png" class="ratingstar" />'; 
        )
        return $stars;
    }
    else
    {
        for(
            i=0;
            i<$averageuserrating-1; 
            $i++;$stars .='<img src="images/star.png" class="ratingstar" />' 
        )
        $stars .= '<img src="images/halfstar.png" class="ratingstar" />'; 
        return $stars;
    }

}

Answer 7

$fullstar = '<img src="images/star.png" class="ratingstar" />';
$halfstar = '<img src="images/halfstar.png" class="ratingstar" />';

$value=2.5;//some rating

$number = number_format ( $value, 1 );
$fs = floor ( $number );  //full stars
$hs=(($value*10)%10)/5;   //half stars


while($fs>0)
{
echo $fullstar;
$fs=$fs-1;
}

if($hs==1)
echo $halfstar;

PHP根据值返回一定数量的代码

7 个答案: