我想mongodb查询这个sql查询:
select x,y,message,foo from messege where x=1 and y=1 group by x,y order by _id DESC
但是:
MongoCollection ::组
任何人都可以帮助我吗?
答案 0 :(得分:1)
对于此
select a,b,sum(c) csum from coll where active=1 group by a,b
各自是
db.coll.group(
{key: { a:true, b:true },
cond: { active:1 },
reduce: function(obj,prev) { prev.csum += obj.c; },
initial: { csum: 0 }
});
您无法对从组中获得的结果进行排序,您可以使用sort for find for this for desc -1,1 for asc:.sort({“_ id”: - 1})desc
检查此http://www.mongodb.org/display/DOCS/Aggregation#Aggregation-Group