Question

我有一个JSON对象musicianobj，我在下面粘贴了一个例子：

{
id: "451026389391"
name: "John Frusciante"
type: "profile"
url: "http://open.spotify.com/artist/XXXXXXXXXXXXXX"
}

我是使用Javascript SDK从Facebook API获得的。我可以运行console.log(musicianobj);成功将对象打印到Chrome中的日志，但console.log(musicianobj.name);，console.log(musicianobj[1]);和console.log(musicianobj["name"]);都没有明确原因返回undefined。有什么想法吗？

编辑：以下代码。

var playFriendsTrack = function(friend){
  FB.api("/"+friend+"/music.listens", function(data) {
    var songname = data.data[0].data.song.title;
    var artistname = "";
    FB.api(data.data[0].data.song.id,function(trackdata){
      var musicianobj = trackdata.data.musician;
      console.log(musicianobj);
      console.log(musicianobj["name"]); // Doesn't work
      console.log(musicianobj.name); // Doesn't work
      artistname = musicianobj[1]; // Doesn't work
    });
    if(artistname.length <= 0){
      alert("Error! Please try another friend.")
    }
    }
  );}

Answer 1

你解密了吗？它似乎仍然是一个字符串。

musicianobj = JSON.parse(musicianobj);
console.log(musicianobj.name); // Now this should work

Answer 2

搞定了！我必须在[0]之后加musicianobj。显然我不像我想的那样知道JSON。工作代码粘贴在下面：

var playFriendsTrack = function(friend){
FB.api("/"+friend+"/music.listens", function(data) {
  var songname = data.data[0].data.song.title;
  var artistname = "";
  FB.api(data.data[0].data.song.id,function(trackdata){
    var musicianobj = trackdata.data.musician;
    console.log(musicianobj);
    console.log(musicianobj[0]["name"]);
    console.log(musicianobj[0].name);
    artistname = musicianobj[0].name;
  });
  if(artistname.length <= 0){
    alert("Error! Please try another friend.")
  }
  }
);}

无法访问JSON对象的子级

2 个答案: