编写一个查询,显示累计超过1000个罚款的所有汽车累积的罚款总额

时间:2012-11-23 17:40:46

标签: mysql

我无法弄清楚如何在SQL中编写查询。

这是我的表格,

CREATE TABLE offences (
oOffenceID VARCHAR (30),
oDescription VARCHAR (200),
oMaximumFine INT (10),
CONSTRAINT o_pk
PRIMARY KEY (oOffenceID)
);

CREATE TABLE drivers (
dPersonID VARCHAR (30),
dLicenseNumber INT (20),
dLicenseRemoved ENUM('yes','no'),
dExpiryDate DATE,
CONSTRAINT d_pk
PRIMARY KEY (dLicenseNumber),
CONSTRAINT d_fk
FOREIGN KEY (dPersonId)
REFERENCES People (pPersonID)
);

CREATE TABLE people (
pPersonID VARCHAR (30),
pName VARCHAR (30),
pAddress VARCHAR (50),
pNIN VARCHAR (30),
CONSTRAINT p_pk
PRIMARY KEY (pPersonID)
);

CREATE TABLE vehicle (
vOwnerID VARCHAR (30),
vColour VARCHAR (30),
vModel VARCHAR (30),
vMake VARCHAR (30),
vVehicleID VARCHAR (30),
CONSTRAINT v_pk
PRIMARY KEY (vVehicleID),
CONSTRAINT v_fk
FOREIGN KEY (vOwnerID)
REFERENCES People (pPersonID)
);

CREATE TABLE fines (
fFineID INT (30) AUTO_INCREMENT,
fVehicleID VARCHAR (30),
fPersonID VARCHAR (30),
fTime DATE,
fAmount INT (10),
fOfficerStatement VARCHAR (500),
fOffenceID VARCHAR (30),
CONSTRAINT f_pk
PRIMARY KEY (fFineID),
CONSTRAINT f_fk
FOREIGN KEY (fVehicleID)
REFERENCES vehicle (vVehicleID),
CONSTRAINT f_fk1
FOREIGN KEY (fPersonID)
REFERENCES people (pPersonID),
CONSTRAINT f_fk2
FOREIGN KEY (fOffenceID)
REFERENCES offences (oOffenceID)
);

我需要一个查询,显示汽车的VehicleID,所有者的名字以及累计超过1000个罚款的所有汽车累积的罚款总额。有人能看到怎么做吗?

2 个答案:

答案 0 :(得分:2)

希望这会让你朝着正确的方向前进:

select fVehicleId,p.pName,sum(fi.totalFines) as totalFinesOver1000ForPerson
from 
(select fVehicleId,sum(fAmount) as totalFines
from fines f
group by fVehicleId
having sum(fAmount) > 1000) fi
inner join vehicle v on v.vVehicleID = fi.fVehicleId
inner join people p on v.vOwnerId = p.pPersonId
group by fVehicleId,p.pName;

答案 1 :(得分:0)

Select a.vVehicleID,
       b.pName,
       sum(d.fAmount) fine 
from vehicle a,people b,fines d,drivers e 
where a.vVehicleID=d.vVehicleID and d.fPersonID=e.dPersonID and d.fPersonID=a.vOwnerID and
      b.pPersonID = e.dPersonID 
group by a.vVehicleID,b.pNamem
having fine > 1000;

这应该有效