Question

我想与MYSQL PHPMYADMIN创建表关系。但不是约束。

这就是我所做的：

CREATE TABLE runs (
code_teachers int(8),
code_department int(8),
primary key(code_teachers, code_department),
foreign key(code_teachers)references teachers,
foreign key(code_department)references department
);

因此，您可以看到我正在尝试在教师创建表的code_teachers和部门创建表中的code_department之间创建名为run的表关系。

但是对于一些未知的原因，当我进入desinger时它只是没有建立关系。所以，如果有人知道我的问题的答案，欢迎你告诉我因为你疯了。

Answer 1

你试过吗

FOREIGN KEY ( columnName ) REFERENCES tableName(columnName)

您的查询中似乎缺少

tableName。外键需要引用其他表中的列。

Wikipedia说：

In the context of relational databases, a foreign key is a referential constraint between two tables. A foreign key is a field in a relational table that matches a candidate key of another table. The foreign key can be used to cross-reference tables.

mySQL.com说：

Foreign key relationships involve a parent table that holds the central data values, and a child table with identical values pointing back to its parent. The FOREIGN KEY clause is specified in the child table.

PHP上的MYSQL PHPMYADMIN - 创建表关系

1 个答案: