检测重叠周期的算法

Question

我要检测两个时间段是否重叠 每个时期都有开始日期和结束日期 我需要检测我的第一个时间段（A）是否与另一个时间段（B / C）重叠。
在我的情况下，如果B的起点等于A的结尾，则它们不重叠（反过来） 我发现了以下情况：

所以实际上我这样做是这样的：

tStartA < tStartB && tStartB < tEndA //For case 1
OR
tStartA < tEndB && tEndB <= tEndA //For case 2
OR
tStartB < tStartA  && tEndB > tEndA //For case 3

（案例4在案例1或案例2中被记入帐户）

有效，但似乎效率不高。

所以，首先是c＃中存在一个可以对此进行建模的类（一个时间段），类似于时间跨度，但具有固定的开始日期。

其次：是否已有可以处理此问题的c＃代码（如DateTime类）？

第三：如果不是，你的方法是什么才能使这种比较最快？

Answer 1

简单检查两个时间段是否重叠：

bool overlap = a.start < b.end && b.start < a.end;

或在您的代码中：

bool overlap = tStartA < tEndB && tStartB < tEndA;

（如果您改变主意想要说两个相互接触的时段重叠，请使用<=代替<。）

Answer 2

有一个很棒的图书馆，对CodeProject有很好的评价：http://www.codeproject.com/Articles/168662/Time-Period-Library-for-NET

该库在重叠，交叉等方面做了很多工作。复制/粘贴所有这些都太大了，但是我会看到哪些特定部分对你有用。

Answer 3

您可以创建可重复使用的Range模式类：

public class Range<T> where T : IComparable
{
    readonly T min;
    readonly T max;

    public Range(T min, T max)
    {
        this.min = min;
        this.max = max;
    }

    public bool IsOverlapped(Range<T> other)
    {
        return Min.CompareTo(other.Max) < 0 && other.Min.CompareTo(Max) < 0;
    }

    public T Min { get { return min; } }
    public T Max { get { return max; } }
}

您可以添加合并范围，交叉点等所需的所有方法......

Answer 4

我正在建立预订系统并找到了此页面。我只对范围交叉感兴趣，所以我构建了这个结构;使用DateTime范围就足够了。

您可以检查交叉点并检查特定日期是否在范围内，然后获取 交叉点类型和最重要的：你可以得到相交的范围。

public struct DateTimeRange
{

    #region Construction
    public DateTimeRange(DateTime start, DateTime end) {
        if (start>end) {
            throw new Exception("Invalid range edges.");
        }
        _Start = start;
        _End = end;
    }
    #endregion

    #region Properties
    private DateTime _Start;

    public DateTime Start {
        get { return _Start; }
        private set { _Start = value; }
    }
    private DateTime _End;

    public DateTime End {
        get { return _End; }
        private set { _End = value; }
    }
    #endregion

    #region Operators
    public static bool operator ==(DateTimeRange range1, DateTimeRange range2) {
        return range1.Equals(range2);
    }

    public static bool operator !=(DateTimeRange range1, DateTimeRange range2) {
        return !(range1 == range2);
    }
    public override bool Equals(object obj) {
        if (obj is DateTimeRange) {
            var range1 = this;
            var range2 = (DateTimeRange)obj;
            return range1.Start == range2.Start && range1.End == range2.End;
        }
        return base.Equals(obj);
    }
    public override int GetHashCode() {
        return base.GetHashCode();
    }
    #endregion

    #region Querying
    public bool Intersects(DateTimeRange range) {
        var type = GetIntersectionType(range);
        return type != IntersectionType.None;
    }
    public bool IsInRange(DateTime date) {
        return (date >= this.Start) && (date <= this.End);
    }
    public IntersectionType GetIntersectionType(DateTimeRange range) {
        if (this == range) {
            return IntersectionType.RangesEqauled;
        }
        else if (IsInRange(range.Start) && IsInRange(range.End)) {
            return IntersectionType.ContainedInRange;
        }
        else if (IsInRange(range.Start)) {
            return IntersectionType.StartsInRange;
        }
        else if (IsInRange(range.End)) {
            return IntersectionType.EndsInRange;
        }
        else if (range.IsInRange(this.Start) && range.IsInRange(this.End)) {
            return IntersectionType.ContainsRange;
        }
        return IntersectionType.None;
    }
    public DateTimeRange GetIntersection(DateTimeRange range) {
        var type = this.GetIntersectionType(range);
        if (type == IntersectionType.RangesEqauled || type==IntersectionType.ContainedInRange) {
            return range;
        }
        else if (type == IntersectionType.StartsInRange) {
            return new DateTimeRange(range.Start, this.End);
        }
        else if (type == IntersectionType.EndsInRange) {
            return new DateTimeRange(this.Start, range.End);
        }
        else if (type == IntersectionType.ContainsRange) {
            return this;
        }
        else {
            return default(DateTimeRange);
        }
    }
    #endregion


    public override string ToString() {
        return Start.ToString() + " - " + End.ToString();
    }
}
public enum IntersectionType
{
    /// <summary>
    /// No Intersection
    /// </summary>
    None = -1,
    /// <summary>
    /// Given range ends inside the range
    /// </summary>
    EndsInRange,
    /// <summary>
    /// Given range starts inside the range
    /// </summary>
    StartsInRange,
    /// <summary>
    /// Both ranges are equaled
    /// </summary>
    RangesEqauled,
    /// <summary>
    /// Given range contained in the range
    /// </summary>
    ContainedInRange,
    /// <summary>
    /// Given range contains the range
    /// </summary>
    ContainsRange,
}

Answer 5

此代码检查两个间隔是否重叠。

---------|---|
---|---|                > FALSE
xxxxxxxxxxxxxxxxxxxxxxxxx
-------|---|
---|---|                > FALSE
xxxxxxxxxxxxxxxxxxxxxxxxx
------|---|
---|---|                > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
---|--|                 > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
----|---|
---|-----|              > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
----|-|                 > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
----|--|                > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
---|---|                > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
----|---|               > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
-------|---|            > TRUE
xxxxxxxxxxxxxxxxxxxxxxxxx
---|---|
--------|---|           > TRUE

算法：

x1 < y2
and
x2 > y1

示例12:00 - 12:30与12:30 13:00不重叠

Answer 6

自定义interval-tree结构怎么样？您需要稍微调整一下，以定义两个区域在您的域中“重叠”的含义。

This question可能会帮助您在C＃中找到现成的间隔树实现。

Answer 7

我不相信框架本身就有这个类。也许是第三方图书馆......

但为什么不创建一个Period值对象类来处理这种复杂性呢？这样您就可以确保其他约束，例如验证开始日期和结束日期时间。类似的东西：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Whatever.Domain.Timing {
    public class Period {
        public DateTime StartDateTime {get; private set;}
        public DateTime EndDateTime {get; private set;}

        public Period(DateTime StartDateTime, DateTime EndDateTime) {
            if (StartDateTime > EndDateTime)
                throw new InvalidPeriodException("End DateTime Must Be Greater Than Start DateTime!");
            this.StartDateTime = StartDateTime;
            this.EndDateTime = EndDateTime;
        }


        public bool Overlaps(Period anotherPeriod){
            return (this.StartDateTime < anotherPeriod.EndDateTime && anotherPeriod.StartDateTime < this.EndDateTime)
        }

        public TimeSpan GetDuration(){
            return EndDateTime - StartDateTime;
        }

    }

    public class InvalidPeriodException : Exception {
        public InvalidPeriodException(string Message) : base(Message) { }    
    }
}

通过这种方式，您可以单独比较每个时期......

Answer 8

public class ConcreteClassModel : BaseModel
{
... rest of class

public bool InersectsWith(ConcreteClassModel crm)
    {
        return !(this.StartDateDT > crm.EndDateDT || this.EndDateDT < crm.StartDateDT);
    }
}

[TestClass]
public class ConcreteClassTest
{
    [TestMethod]
    public void TestConcreteClass_IntersectsWith()
    {
        var sutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 01), EndDateDT = new DateTime(2016, 02, 29) };

        var periodBeforeSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 01, 31) };
        var periodWithEndInsideSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 10), EndDateDT = new DateTime(2016, 02, 10) };
        var periodSameAsSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 01), EndDateDT = new DateTime(2016, 02, 29) };

        var periodWithEndDaySameAsStartDaySutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 02, 01) };
        var periodWithStartDaySameAsEndDaySutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 29), EndDateDT = new DateTime(2016, 03, 31) };
        var periodEnclosingSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 01, 01), EndDateDT = new DateTime(2016, 03, 31) };

        var periodWithinSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 010), EndDateDT = new DateTime(2016, 02, 20) };
        var periodWithStartInsideSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 02, 10), EndDateDT = new DateTime(2016, 03, 10) };
        var periodAfterSutPeriod = new ConcreteClassModel() { StartDateDT = new DateTime(2016, 03, 01), EndDateDT = new DateTime(2016, 03, 31) };

        Assert.IsFalse(sutPeriod.InersectsWith(periodBeforeSutPeriod), "sutPeriod.InersectsWith(periodBeforeSutPeriod) should be false");
        Assert.IsTrue(sutPeriod.InersectsWith(periodWithEndInsideSutPeriod), "sutPeriod.InersectsWith(periodEndInsideSutPeriod)should be true");
        Assert.IsTrue(sutPeriod.InersectsWith(periodSameAsSutPeriod), "sutPeriod.InersectsWith(periodSameAsSutPeriod) should be true");

        Assert.IsTrue(sutPeriod.InersectsWith(periodWithEndDaySameAsStartDaySutPeriod), "sutPeriod.InersectsWith(periodWithEndDaySameAsStartDaySutPeriod) should be true");
        Assert.IsTrue(sutPeriod.InersectsWith(periodWithStartDaySameAsEndDaySutPeriod), "sutPeriod.InersectsWith(periodWithStartDaySameAsEndDaySutPeriod) should be true");
        Assert.IsTrue(sutPeriod.InersectsWith(periodEnclosingSutPeriod), "sutPeriod.InersectsWith(periodEnclosingSutPeriod) should be true");

        Assert.IsTrue(sutPeriod.InersectsWith(periodWithinSutPeriod), "sutPeriod.InersectsWith(periodWithinSutPeriod) should be true");
        Assert.IsTrue(sutPeriod.InersectsWith(periodWithStartInsideSutPeriod), "sutPeriod.InersectsWith(periodStartInsideSutPeriod) should be true");
        Assert.IsFalse(sutPeriod.InersectsWith(periodAfterSutPeriod), "sutPeriod.InersectsWith(periodAfterSutPeriod) should be false");
    }
}

感谢上述答案，它帮助我为MVC项目编写上述代码。

注意StartDateDT和EndDateDT是dateTime类型

Answer 9

--logic FOR OVERLAPPING DATES
DECLARE @StartDate datetime  --Reference start date
DECLARE @EndDate datetime    --Reference end date
DECLARE @NewStartDate datetime --New Start date
DECLARE @NewEndDate datetime   --New End Date

Select 
(Case 
    when @StartDate is null 
        then @NewStartDate
    when (@StartDate<@NewStartDate and  @EndDate < @NewStartDate)
        then @NewStartDate
    when (@StartDate<@NewStartDate and  @EndDate > @NewEndDate)
        then @NewStartDate
    when (@StartDate<@NewStartDate and  @EndDate > @NewStartDate)
        then @NewStartDate  
    when (@StartDate>@NewStartDate and  @NewEndDate < @StartDate)
        then @NewStartDate
    else @StartDate end) as StartDate,  

(Case 
    when @EndDate is null   
        then @NewEndDate
    when (@EndDate>@NewEndDate and @Startdate < @NewEndDate)
        then @NewEndDate
    when (@EndDate>@NewEndDate and @Startdate > @NewEndDate)
        then @NewEndDate
    when (@EndDate<@NewEndDate and @NewStartDate > @EndDate)
        then @NewEndDate
    else @EndDate end) as EndDate

Distrubution logic

Answer 10

试试这个。无论方法的输入参数的顺序如何，此方法都将确定（两个）日期跨度是否重叠。这也可以与两个以上的日期范围一起使用，通过单独检查每个日期范围组合（例如，具有3个日期范围，针对span1运行span2，针对{{1}运行span2 }和span3反对span1）：

span3

测试：

public static class HelperFunctions
{
    public static bool AreSpansOverlapping(Tuple<DateTime,DateTime> span1, Tuple<DateTime,DateTime> span2, bool includeEndPoints)
    {
        if (span1 == null || span2 == null)
        {
            return false;
        }
        else if ((new DateTime[] { span1.Item1, span1.Item2, span2.Item1, span2.Item2 }).Any(v => v == DateTime.MinValue))
        {
            return false;
        }
        else
        {
            if (span1.Item1 > span1.Item2)
            {
                span1 = new Tuple<DateTime, DateTime>(span1.Item2, span1.Item1);
            }
            if (span2.Item1 > span2.Item2)
            {
                span2 = new Tuple<DateTime, DateTime>(span2.Item2, span2.Item1);
            }

            if (includeEndPoints)
            {
                return 
                ((
                    (span1.Item1 <= span2.Item1 && span1.Item2 >= span2.Item1) 
                    || (span1.Item1 <= span2.Item2 && span1.Item2 >= span2.Item2)
                ) || (
                    (span2.Item1 <= span1.Item1 && span2.Item2 >= span1.Item1) 
                    || (span2.Item1 <= span1.Item2 && span2.Item2 >= span1.Item2)
                ));
            }
            else
            {
                return 
                ((
                    (span1.Item1 < span2.Item1 && span1.Item2 > span2.Item1) 
                    || (span1.Item1 < span2.Item2 && span1.Item2 > span2.Item2)
                ) || (
                    (span2.Item1 < span1.Item1 && span2.Item2 > span1.Item1) 
                    || (span2.Item1 < span1.Item2 && span2.Item2 > span1.Item2)
                ) || (
                    span1.Item1 == span2.Item1 && span1.Item2 == span2.Item2
                ));
            }
        }
    }
}

Answer 11

这是我的解决方案：

    public static bool OverlappingPeriods(DateTime aStart, DateTime aEnd, DateTime bStart, DateTime bEnd)
    {
        if (aStart > aEnd)
            throw new ArgumentException("A start can not be after its end.");

        if(bStart > bEnd)
            throw new ArgumentException("B start can not be after its end.");

        return !((aEnd < bStart && aStart < bStart) ||
                 (bEnd < aStart && bStart < aStart));
    }

我以100％的覆盖率对其进行了单元测试。

@Dushan Gajik，你在上一个案例中似乎有错误 - 它可能是假的。

  

xxxxxxxxxxxxxxxxxxxxxxxxx

     

--- | --- |

     

-------- | --- |

     

TRUE

Answer 12

检查此简单方法（建议将此方法放入您的dateUtility

public static bool isOverlapDates(DateTime dtStartA, DateTime dtEndA, DateTime dtStartB, DateTime dtEndB)
        {
            return dtStartA < dtEndB && dtStartB < dtEndA;
        }