也许这是一个基本问题,但无法回答,并感谢您的帮助:)
我在MySQL中有以下表格:
create table anotation
(
chromosome enum
(
'Chr1',
'Chr2',
'Chr3',
'Chr4',
'Chr5',
'ChrC',
'ChrM'
),
version varchar(10),
type enum
(
'CDS',
'chromosome',
'exon',
'five_prime_UTR',
'gene',
'mRNA',
'mRNA_TE_gene',
'miRNA',
'ncRNA',
'protein',
'pseudogene',
'pseudogenic_exon',
'pseudogenic_transcript',
'rRNA',
'snRNA',
'snoRNA',
'tRNA',
'three_prime_UTR',
'transposable_element_gene'
),
strand enum
(
'+',
'-'
),
phase tinyint,
atrributes text
);`
它有大约600,000个值,我正在进行以下查询:
select distinct
anot_1.chromosome,
anot_1.start,
anot_1.end,
anot_1.atrributes
from
anotation anot_1,
anotation anot_2
where
anot_1.type='CDS'
and
anot_2.type='protein'
and
anot_1.chromosome!='ChrM'
and
anot_1.chromosome!='ChrC'
and
anot_1.chromosome=anot_2.chromosome
and
(
(
anot_2.start=anot_1.start
and
anot_1.end!=anot_2.end
and
anot_2.strand='+'
)
or
(
anot_2.start!=anot_1.start
and
anot_1.end=anot_2.end
and
anot_2.strand='-'
)
);
并且需要很长时间才能完成,但是当我执行查询(同一个,但是我从OR中删除其中一个条件)时,它几乎立即运行:
select distinct
anot_1.chromosome,
anot_1.start,
anot_1.end,
anot_1.atrributes
from
anotation anot_1,
anotation anot_2
where
anot_1.type='CDS'
and
anot_2.type='protein'
and
anot_1.chromosome!='ChrM'
and
anot_1.chromosome!='ChrC'
and
anot_1.chromosome=anot_2.chromosome
and
anot_2.start=anot_1.start
and
anot_1.end!=anot_2.end
and
anot_2.strand='+';`
任何人都知道发生了什么事,如果有,我该如何解决? 谢谢!!!
答案 0 :(得分:0)
这不是一个解决方案(我同意上面关于索引的评论),但是我已经改变了你的SQL以使用一对左外连接而不是当前在JOIN中有OR的SQL。
虽然我不希望这在性能上有太大差异,但它可能会帮助您和其他人看到查询正在做什么: -
SELECT distinct anot_1.chromosome, anot_1.start, anot_1.end, anot_1.atrributes
FROM anotation anot_1,
LEFT OUTER JOIN anotation anot_2 ON anot_1.chromosome = anot_2.chromosome AND anot_1.start = anot_2.start AND anot_1.end != anot_2.end AND anot_2.strAND = '+' AND anot_2.type='protein'
LEFT OUTER JOIN anotation anot_3 ON anot_1.chromosome = anot_3.chromosome AND anot_1.end = anot_3.end AND anot_1.start != anot_3.start AND anot_3.strAND = '+' AND anot_3.type='protein'
WHERE anot_1.type = 'CDS'
AND anot_1.chromosome != 'ChrM'
AND anot_1.chromosome != 'ChrC'
AND (anot_2.chromosome IS NOT NULL
OR anot_3.chromosome IS NOT NULL)
答案 1 :(得分:0)
我首先要清理你的查询,将它们拆开并进行联合
select
CDS.chromosome,
CDS.start,
CDS.end,
CDS.atrributes
from
(
select
a.chromosome,
a.start,
a.end,
a.attribures,
from
anotation a,
where
a.type='CDS'
and
not a.chromosome IN ('ChrM', 'ChrC')
) CDS
join
(
select
a.strand,
from
anotation a,
where
a.type='protien'
) Protien
on
CDS.chromosome = Protien.chromosome
and
CDS.start = Protien.start
and
CDS.end != Protien.end
where
Protien.strand = '+'
union
select
CDS.chromosome,
CDS.start,
CDS.end,
CDS.atrributes
from
(
select
a.chromosome,
a.start,
a.end,
a.attribures,
from
anotation a,
where
a.type='CDS'
and
not a.chromosome IN ('ChrM', 'ChrC')
) CDS
join
(
select
a.strand,
from
anotation a,
where
a.type='protien'
) Protien
on
CDS.chromosome = Protien.chromosome
and
CDS.start != Protien.start
and
CDS.end = Protien.end
where
Protien.strand = '-'