Question

伪代码：

NSArray *arr1 = {"mike","george","Tim","Tom"...}
NSArray *arr2 = {"mike","george","Chris","Adam"...}
NSArray *arr3 = {"Don","george","mike","Tom"...}
NSArray *arr4 = {"george","Nicole","Moe","mike"...}

//Add these arrays to the dictionary
for(int i=0; i<n, i++)
   [dictionary addObject:arr[i]];

我想找到所有数组中存在的重复值，而不是一些。在此示例中，值为{“george”，“mike”}。

Answer 1

NSArray *arr1 = @[@"mike",@"george",@"Tim",@"Tom" ];
NSArray *arr2 = @[@"mike",@"george",@"Chris",@"Adam" ];
NSArray *arr3 = @[@"Don",@"george",@"mike",@"Tom" ];
NSArray *arr4 = @[@"george",@"Nicole",@"Moe",@"mike" ];

NSMutableSet *intersection = [NSMutableSet setWithArray:arr1];
[intersection intersectSet:[NSSet setWithArray:arr2]];
[intersection intersectSet:[NSSet setWithArray:arr3]];
[intersection intersectSet:[NSSet setWithArray:arr4]];

NSArray *duplicates = [intersection allObjects];

NSLog(@"duplicates=%@", duplicates);

duplicates包含一个数组，其值显示在all：

中

duplicates=(
  mike,
  george
)

Answer 2

假设dictionary实际上是一个NSMutableArray，那么这样的东西就可以了：

NSMutableArray *results = [[NSMutableArray alloc] init];

for(NSString *name in [dictionary objectAtIndex:0]) {
    bool valid = true;
    for(int i=1;i<[dictionary count];i++) {
        if([[dictionary objectAtIndex:i] indexOfObject:name]==NSNotFound) {
            valid=false;
            break;
        }
    }
    if(valid)
        [results addObject:name];
}

如何在NSMutableDictionary中找到重复项？

2 个答案: