某些应用在iOS 6中显示带有共享选项的默认操作表。
Social Framework只有两个类,一个用于撰写,一个用于请求。
我发现的是使用SLComposeViewController为特定服务进行编写,在显示之前我必须手动查询服务是否可用。然后我还必须使用自己的图标创建自己的操作表。
这些应用如何在iOS 6中显示此默认共享选项操作表?或者他们是否使用开源框架?
答案 0 :(得分:223)
另一个答案中陈述的UIActivityViewController使这一点变得微不足道。您所要做的就是指定要共享的文本/图像/ URL并以模态方式显示活动视图控制器,iOS将自动显示所有适用的共享服务。例子:
- (void)shareText:(NSString *)text andImage:(UIImage *)image andUrl:(URL *)url
{
NSMutableArray *sharingItems = [NSMutableArray new];
if (text) {
[sharingItems addObject:text];
}
if (image) {
[sharingItems addObject:image];
}
if (url) {
[sharingItems addObject:url];
}
UIActivityViewController *activityController = [[UIActivityViewController alloc] initWithActivityItems:sharingItems applicationActivities:nil];
[self presentViewController:activityController animated:YES completion:nil];
}
func share(sharingText: String?, sharingImage: UIImage?, sharingURL: URL?) {
let sharingItems:[AnyObject?] = [
sharingText as AnyObject,
sharingImage as AnyObject,
sharingURL as AnyObject
]
let activityViewController = UIActivityViewController(activityItems: sharingItems.compactMap({$0}), applicationActivities: nil)
if UIDevice.current.userInterfaceIdiom == .pad {
activityViewController.popoverPresentationController?.sourceView = view
}
present(activityViewController, animated: true, completion: nil)
}
答案 1 :(得分:39)
添加此项以使用UIActivityViewController
。
-(IBAction)shareButtonPressed:(id)sender {
NSLog(@"shareButton pressed");
NSString *texttoshare = _txt; //this is your text string to share
UIImage *imagetoshare = _img; //this is your image to share
NSArray *activityItems = @[texttoshare, imagetoshare];
UIActivityViewController *activityVC = [[UIActivityViewController alloc] initWithActivityItems:activityItems applicationActivities:nil];
activityVC.excludedActivityTypes = @[UIActivityTypeAssignToContact, UIActivityTypePrint];
[self presentViewController:activityVC animated:TRUE completion:nil];
}