我正在使用下面的代码片段在Python中编写HTTP服务器。服务器运行良好,直到发生一些IOError导致它重新启动。我的重启处理有问题,因为服务器启动正常,但之后不接受任何请求。
此代码有什么问题吗?
#!/bin/python
from BaseHTTPServer import HTTPServer
import json
import config
import time
import socket
from SimpleHTTPServer import SimpleHTTPRequestHandler
from SocketServer import BaseServer
class MyHandler(SimpleHTTPRequestHandler):
def parseArgs(self):
args = {}
try:
config.logging.info(self.path)
args_list = self.path.split("?")[1].split("&")
for entry in args_list:
args[entry.split("=")[0]] = entry.split("=")[1]
except IndexError:
pass
return args
def do_GET(self):
try:
response = {}
args = self.parseArgs()
config.logging.debug("Handle the request")
self._handle_request(args, response)
config.logging.debug("Write the header back to the client.")
self.send_response(200)
self.send_header('Access-Control-Allow-Origin', '*')
self.send_header('Content-Type:', 'application/json; charset=UTF-8')
self.end_headers()
config.logging.debug("Finish writing the header and start writing JSON response.")
json_encoded = json.dumps(response)
config.logging.debug(json_encoded)
self.wfile.write(json_encoded)
config.logging.debug("JSON Response written successfully.")
except Exception as e:
config.logging.exception('Exception occurs when writing back the response.')
return
def _handle_request(self, args, response):
try:
response["sysTime"] = long(round(time.time() * 1000))
if not "cmd" in args:
response["message"] = "Error: No command provided."
else:
response["message"] = args['cmd']
except Exception as e:
response["message"] = "Error: Exception occurs (check logs)."
config.logging.exception('Exception occurs when handling request.')
def do_POST(self):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers()
self.wfile.write("Nothing here :( ")
def main():
while True:
try:
httpd = HTTPServer(('', config.listening_port), MyHandler)
sa = httpd.socket.getsockname()
msg = "Serving HTTP on " + sa[0] + " port " + str(sa[1]) + "..."
print msg
config.logging.info(msg)
httpd.serve_forever()
except KeyboardInterrupt:
print '^C received, shutting down server'
config.logging.info('^C received, shutting down server')
httpd.socket.close()
break
except Exception as e:
httpd.shutdown()
httpd.socket.close()
print "Error occurs. Retry in 5 seconds"
config.logging.exception('Exception occurs. Retry in 5 seconds.')
time.sleep(5)
if __name__ == '__main__':
main()
很抱歉错过了模块配置。
import logging
# global variables
listening_port = 9001
logging.basicConfig(filename='error.log', level=logging.INFO, format='%(asctime)s - %(levelname)s - %(message)s', datefmt='%m/%d/%Y %I:%M:%S %p')
运行此功能的一个网址是http://localhost:9001/?cmd=some_command
。只需在服务器启动后将其粘贴到任何浏览器中即可。
修改
我想这与KVM或我在公司机器上设置的方式有关。由于我的服务器在只能通过ssh访问的KVM上运行,每次我退出ssh会话时,调用上面的url命令(在chrome中),等到chrome通知未连接,返回ssh会话,调用url再次命令,错误发生了。
我将调试消息放在self.send_response(200)
中do_GET()中的写响应之间。当异常发生时,这就是我得到的痕迹。我想这与log_message中的sys.stderr.write
有关。
11/23/2012 10:58:29 AM - INFO - Handle the request
11/23/2012 10:58:29 AM - INFO - /?cmd=get_info&uid=pp
11/23/2012 10:58:29 AM - INFO - Write the header back to the client.
11/23/2012 10:58:29 AM - ERROR - Exception occurs when writing back the response.
Traceback (most recent call last):
File "service.py", line 57, in do_GET
self.send_response(200)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 385, in send_response
self.log_request(code)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 422, in log_request
self.requestline, str(code), str(size))
File "/usr/lib/python2.7/BaseHTTPServer.py", line 458, in log_message
format%args))
IOError: [Errno 5] Input/output error
修改
当我覆盖log_message()
无所事事时,问题就消失了。我知道这只隐藏了这个问题,但至少它暂时适合我。
答案 0 :(得分:0)
sys.stderr将消息写入标准输出,通常是启动程序的shell控制台。因此,如果shell控制台关闭,sys.stderr.writes将引发IO错误。
因此问题的根本原因是log_message()函数中的sys.stderr.write尝试将消息写入最初启动python程序的ssh shell控制台(标准输出),因此如果保留ssh会话活着,这个问题不会发生。但是如果你退出原来的ssh会话,shell控制台会关闭,那么sys.stderr.write就不会把消息写入原来的控制台,然后发生IO错误.... log_message通常写这样的东西:
127.0.0.1 - - [01/Dec/2015 20:16:32] "GET / HTTP/1.1" 200 -
所以解决方案是运行你的python脚本,将标准输出重定向到/ dev / null,如下所示:
python your_script.py > /dev/null 2>&1 &
Holp它有帮助。