Question

我需要帮助才能创建查询。我的问题是我有一个StartDate和EndDate，需要在60分钟的集团中分开。

DECLARE @STARTDATE AS SMALLDATETIME
DECLARE @ENDDATE AS SMALLDATETIME

SET @STARTDATE = '2012-11-21 11:03:00'
SET @ENDDATE = '2012-11-21 13:04:00'

我需要回报：

Hour, Time
11  , 57
12  , 60
13  , 04

Answer 1

您可以使用递归CTE。例如：

declare @startDate datetime = '2012-11-21 22:05:00'
declare @endDate datetime = '2012-11-22 01:06:00'

; with  TimeList as
        (
        select  @startDate as dt
        union all
        select  dateadd(hour, 1, dateadd(hour, datediff(hour, 0, dt), 0))
        from    TimeList
        where   dateadd(hour, 1, dt) < @endDate
        )
select  dt
from    TimeList
union all
select  @endDate

代码段dateadd(hour, datediff(hour, 0, dt), 0)会删除日期中的小时和分钟。它是通过计算自约会0以来的小时数，然后再添加到目前为止的小时数0来实现的。

Live example at SQL Fiddle.

Answer 2

我不确定我是否理解你，但这会在你的开始日期之后每隔60分钟返回一小时和一分钟。

DECLARE @STARTDATE AS SMALLDATETIME
DECLARE @ENDDATE AS SMALLDATETIME

DECLARE @time AS TABLE(id int identity(1,1), [hour] int, [time] int)

SET @STARTDATE = '2012-11-21 11:03:00'
SET @ENDDATE = '2012-11-21 13:04:00'

WHILE @STARTDATE < @ENDDATE
BEGIN
    SELECT @STARTDATE = DATEADD(MINUTE,60,@STARTDATE)
    INSERT INTO @time (hour,time)
    VALUES(DATEPART(HOUR,@STARTDATE),DATEPART(MINUTE,@STARTDATE))
END

SELECT * FROM @time

Answer 3

你可以分三件做。第一件是第一个小时，第60件减去分钟值，第二件是时间= 60表示从开始+ 1到结束之间的所有小时，第三件是结束分钟

然后将它们插入到临时表中，就像abstractChaos所做的那样。

像AbstractChaos一样插入临时表：

DECLARE @STARTDATE AS SMALLDATETIME
DECLARE @ENDDATE AS SMALLDATETIME

DECLARE @TIME AS TABLE(id INT IDENTITY(1,1), [HOUR] INT, [TIME] INT)

SET @STARTDATE = '2012-11-21 11:03:00'
SET @ENDDATE = '2012-11-21 13:04:00'

INSERT INTO @TIME (HOUR,TIME) 
VALUES (datepart(HOUR,@startdate) ,60 - datepart(MINUTE,@startdate) )

WHILE @STARTDATE < @ENDDATE
BEGIN
    SELECT @STARTDATE = DATEADD(MINUTE,60,@STARTDATE)
    INSERT INTO @TIME (HOUR,TIME) 
    VALUES(datepart(HOUR,@STARTDATE) , 60) 
END

INSERT INTO @TIME (HOUR,TIME) 
VALUES(datepart(HOUR,@enddate) , datepart(MINUTE,@startdate))

SQL单独的开始日期和结束日期

3 个答案: