Question

我需要从每天和每个团队的数据库中选择一些信息。我想知道每个团队每天购买的物品数量。例如，如果在2012-11-21购买了6件物品，我希望我的结果显示：团队1买了3件物品，团队2 - 2件物品和最后一团队1件物品。我可以使用以下内容获取一个团队的信息：

select count(CONVERT(date, getdate())) as Team1
from items
where team = 1
group by CONVERT(date, getdate())

但我不确定如何获得所有团队所需的信息。

修改

我需要结果是这样的：

Date      |Team1   | Team2   | Team3  
2012-11-21|2 items | 3 items | 0 items

我的表结构是这样的：Date, Product, Price, Team。

Answer 1

您需要GROUP BY团队和日期。

SELECT datecol, team, COUNT(*)
FROM items
GROUP BY datecol, team

根据您的更新要求而不知道您的DBMS是什么：

SELECT a.datecol AS 'Date',
    (SELECT COUNT(*) FROM items WHERE datecol = a.datecol AND team = '1') AS 'Team1',
    (SELECT COUNT(*) FROM items WHERE datecol = a.datecol AND team = '2') AS 'Team2',
    (SELECT COUNT(*) FROM items WHERE datecol = a.datecol AND team = '3') AS 'Team3'
FROM items a
GROUP BY a.datecol

Answer 2

你需要的是PIVOT你的桌子是这样的：

SELECT 
  Date,
  SUM(CASE WHEN team = 'team1' THEN 1 ELSE 0 END) 'team1',
  SUM(CASE WHEN team = 'team2' THEN 1 ELSE 0 END) 'team2',
  SUM(CASE WHEN team = 'team3' THEN 1 ELSE 0 END) 'team3'
FROM Tablename
GROUP BY date;

每个团队每天sql选择信息

2 个答案: