如何根据排名编写选择查询？

Question

我有一张桌子

表1

id   city    projects       Rank
----------------------------------
1    che        p2           2
2    bang       p1           1
3    che        p4           1
4    bang       p3           2
5    bang       p5           3
6    gur        p6           1
7    gur        p7           2

基于排名我想选择城市和项目 我想要这样

   bang       p1            1
    che        p4           1
    gur        p6           1
    che        p2           2
    bang       p3           2
    gur        p7           2
    bang       p5           3

从table1中选择*，其中Rank =？

Answer 1

select city,project,rank from table1 order by rank,project,city

Answer 2

我希望这会对你有所帮助：

select city, projects, Rank from table1 
order by Rank, city, projects

您也可以使用order by子句中的位置：

select city, projects, Rank from table1 
order by 3,1,2

底部有0的解决方案：

 select city, projects, Rank from table1 
    order by
    case 
     when Rank>0 then 1
     else 2
    end,
    Rank, city, projects

Answer 3

试试这个

 select city, projects, Rank from table order by Rank

Answer 4

在查询中使用ORDER BY子句。

SELECT city, projects, rank FROM table1 
order by rank

Answer 5

这里很多答案都很好。

然而，通常的做法是在SQL中使用UPPERCASE语言结构：

SELECT city,project,rank FROM table1 ORDER BY rank,project;

： - ）

Answer 6

试试这个......

select city,projects,rank from table1 group by rank order by rank,city,projects;