使用SQL like运算符

Question

由于某种原因，我无法让这个SQL查询工作。我能做错什么？我是否正确连接？

$search_query= "SELECT * FROM users WHERE lname LIKE %'".$search_term."'%"

Answer 1

将代码重写为：

$search_query= "SELECT * FROM users WHERE lname LIKE '%".$search_term."%'"

Answer 2

$search_query = "SELECT * FROM users WHERE lname LIKE '%".$search_term."%'";

Answer 3

您将%放在单引号之外。

$search_query= "SELECT * FROM users WHERE lname LIKE '%".$search_term."%'";

Answer 4

您应该将百分比字符放在引号内：

$search_query= "SELECT * FROM users WHERE lname LIKE '%".$search_term."%'"

Answer 5

 $search_query= "SELECT * FROM users
                 WHERE lname LIKE '%".$string."%'";

Answer 6

查看差异

%' '%

$ search_query =“SELECT * FROM users WHERE lname LIKE'％”。$ search_term。“％'”;