我被要求创建一个轮询活动目录的控制台应用程序。 (C. \ TEMP \输入)
当文件带有(filename).SUCCESS
时,将检索文件名以运行SQL查询。所以
IF fileextension = SUCCESS
使用filename运行SQL查询以更改SQL表中的值。
将原始文件移至c:\temp\Input\Processed
非常感谢任何帮助或提示。
更新:
嗨,通过对各个网站的一些看法,我想出了以下内容。暂时忘记SQL,我只在文件名和文件的移动之后,但我得到一个IO异常,该文件已被使用:
导入System.IO 导入System.String 模块模块1
Dim fileName As String = "C:\temp\Input\NR12345.success"
Dim pathname As String = "C:\temp\Input\"
Dim result As String
Dim sourceDir As String = "C:\temp\Input\"
Dim processedDir As String = "C:\temp\Input\Processed\"
Dim fList As String() = Directory.GetFiles(sourceDir, "*.success")
Sub Main()
result = Path.GetFileName(fileName)
Console.WriteLine("GetFileName('{0}') returns '{1}'", fileName, result)
result = Path.GetFileName(pathname)
Console.WriteLine("GetFileName('{0}') returns '{1}'", pathname, result)
Call MySub()
End Sub
Sub MySub()
'Move Files
For Each f As String In fList
'Remove path from the file name.
Dim fName As String = f.Substring(sourceDir.Length = 0)
Dim sourceFile = Path.Combine(sourceDir, fName)
Dim processedFileDir = Path.Combine(processedDir, fName)
' Use the Path.Combine method to safely append the file name to the path.
' Will overwrite if the destination file already exists.
File.Copy(Path.Combine(sourceDir, fName), Path.Combine(processedDir, fName), True)
'File.Copy(sourceFile, processedFileDir)
Next f
End Sub
结束模块
答案 0 :(得分:2)
我以前用过这个:
在轮询目录以获取结构和文件详细信息等方面非常有用。
然后,您可以使用this获取文件的扩展名,如果符合您的条件,则执行一些操作。
这些链接附带示例,所以尽情享受!!
Sub MySub()
'Move Files
For Each f As String In fList
Dim fInfo As FileInfo = New FileInfo(f)
Dim fName As String = fInfo.Name
Dim processedFileDir = Path.Combine(processedDir, fName)
' Use the Path.Combine method to safely append the file name to the path.
' Will overwrite if the destination file already exists.
File.Copy(fInfo.FullName, processedFileDir, True)
Next f
End Sub