Question

我试图改善我的javascript，在这里遇到一些死胡同。

var schemes = {
    "own" : {
        "creatures" : ["creature1","creature2","creature3","creature4"],
        "spells" : ["spell1","spell2","spell3","spell4"],
        "items" : ["item1","item2","item3","item4"]
    },
    "enemy" : {
        "creatures" : ["creature1","creature2","creature3","hidden"],
        "spells" : ["spell1","spell2","hidden","hidden"],
        "items" : ["item1","item2","item3","hidden"]
    }
};

这是我的阵列。

我然后尝试为每个人做一个（我从php知道），但似乎javascript认为方案是一个对象，因此无法做到：

for (var i=0;i<schemes.length;i++) {
 //code 
}

我错过了什么？ schemes.length表示undefined

Answer 1

schemes确实是一个“对象”，因此没有.length。

您可以使用Object.keys(schemes)获取密钥数组，或者：

for (var key in schemes) {
    var el = schemes[key];
     ...
}

Answer 2

您错过了schemes实际上是一个对象而不是一个数组的事实。

请考虑以下事项：

myobject = { 'a' : 1, 'b' : 2, 'c' : 3 } // this is an object

myarray = [ 1, 2, 3 ] // this is an array

你可以用这些变量做些什么：

for (var key in myobject) {
    console.log(key + ": " + myobject[key]);
}

for (var i = 0; i < myarray.length; i++) {
    console.log('Value at index ' + i + ':' + myarray[i]);
}

Answer 3

方案是一个对象。我想你想把它变成一个对象数组。

var schemes = [{
    "own" : {
        "creatures" : ["creature1","creature2","creature3","creature4"],
        "spells" : ["spell1","spell2","spell3","spell4"],
        "items" : ["item1","item2","item3","item4"]
    },
    "enemy" : {
        "creatures" : ["creature1","creature2","creature3","hidden"],
        "spells" : ["spell1","spell2","hidden","hidden"],
        "items" : ["item1","item2","item3","hidden"]
    }
}];

然后您可以按如下方式遍历数组：

for (var i=0;i<schemes.length;i++) {
  alert(schemes[i].creatures[1]); //alerts creature1 (2x)
}

javascript数组基础知识

3 个答案: