Question

好的，尝试创建一个我可以传递变量的函数，它将搜索一个静态的当前硬编码多维数组中的键，并返回与找到的键匹配的数组（如果找到）。

这就是我到目前为止所做的。

public function teamTypeMapping($teamType)
{
    //we send the keyword football, baseball, other, then we return the array associated with it.
    //eg: we send football to this function, it returns an array with nfl, college-football
    $mappings = array(
                "football" => array('nfl', 'college-football'),
                "baseball" => array('mlb', 'college-baseball'),
                "basketball" => array('nba', 'college-basketball'),
                "hockey" => array('nhl', 'college-hockey'),
                );
    foreach($mappings as $mapped => $item)
    {
        if(in_array($teamType, $item)){return $mapped;}
    }
    return false;
}

我想打个电话，例如：

teamTypeMapping("football");

Amd让它返回与关键“足球”相关联的阵列，我已经尝试了几种方式，每次我都错了，也许我错过了一些东西，所以我现在就提出一些建议。< / p>

Answer 1

它不起作用的原因是你循环遍历$ mappings数组，并试图查看$ teamType是否在$ item中。

您的方法存在两个问题：

你正在寻找$ item（这是'足球'的数组（'nfl'，'college-football'））。这是不正确的。
您正在使用in_array（）来检查数组中是否存在“值”，而不是您使用过的“键”。您可能想看一下array_key_exists()函数 - 我认为这就是您的意思。

我个人的偏好是使用isset（）而不是array_key_exists（）。语法略有不同，但两者都做同样的工作。

请参阅下面的修订解决方案：

public function teamTypeMapping($teamType)
{
    //we send the keyword football, baseball, other, then we return the array associated with it.
    //eg: we send football to this function, it returns an array with nfl, college-football
    $mappings = array(
                "football" => array('nfl', 'college-football'),
                "baseball" => array('mlb', 'college-baseball'),
                "basketball" => array('nba', 'college-basketball'),
                "hockey" => array('nhl', 'college-hockey'),
                );
    if (isset($mappings[$teamType])) 
    {
        return $mappings[$teamType];
    }
    return false;
}

Answer 2

我检查了你的功能

public function teamTypeMapping($teamType)
{
    //we send the keyword football, baseball, other, then we return the array associated with it.
    //eg: we send football to this function, it returns an array with nfl, college-football
    $mappings = array(
                "football" => array('nfl', 'college-football'),
                "baseball" => array('mlb', 'college-baseball'),
                "basketball" => array('nba', 'college-basketball'),
                "hockey" => array('nhl', 'college-hockey'),
                );
    foreach($mappings as $mapped => $item)
    {
        if(in_array($teamType, $item)){return $mapped;}
    }
    return false;
}

当你想打电话时，例如：

teamTypeMapping("football");

然后它返回false。

解决方案是如果您想要阵列，那么您需要

foreach($mappings as $mapped => $item)
{
    if($mapped == $teamType){return $mapped;}
}

数组映射功能，每次都返回false

2 个答案: