我想替换XML节点的innertext,我的名为test.xml
的XML文件是
<?xml version="1.0" encoding="utf-8"?>
<ads>
<loop>no</loop>
<item>
<description>Description 1</description>
</item>
<item>
<description>Text in item2</description>
</item>
<item>
<description>Let play with this XML</description>
</item>
</ads>
我想更改loop
和description
标记的值,
它应该保存在test.xml
中:
<?xml version="1.0" encoding="utf-8"?>
<ads>
<loop>yes</loop>
<item>
<description>Description Changing Here</description>
</item>
<item>
<description>Changing text in item2</description>
</item>
<item>
<description>We will play later</description>
</item>
</ads>
我在PHP中尝试过代码:
<?
$file = "test.xml";
$fp = fopen($file, "rb") or die("cannot open file");
$str = fread($fp, filesize($file));
$dom=new DOMDocument();
$dom->formatOutput = true;
$dom->preserveWhiteSpace = false;
$dom->loadXML($str) or die("Error");
//$dom->load("items.xml");
$root=$dom->documentElement; // This can differ (I am not sure, it can be only documentElement or documentElement->firstChild or only firstChild)
$loop=$root->getElementsByTagName('loop')->item(0);//->textContent;
//echo $loop;
if(trim($loop->textContent)=='no')
{
echo 'ok';
$root->getElementsByTagName('loop')->item(0)->nodeValue ='yes';
}
echo "<xmp>NEW:\n". $dom->saveXML() ."</xmp>";
?>
我只尝试使用loop
代码。我不知道如何替换nodevalue
中的description tag
。
当我运行此页面时,它显示如下输出:
ok
NEW:
<?xml version="1.0" encoding="utf-8"?>
<ads>
<loop>yes</loop>
<item>
<description>Description 1</description>
</item>
<item>
<description>Changing text in item2</description>
</item>
<item>
<description>Let play with this XML</description>
</item>
</ads>
它在浏览器中提供值yes
,但不以任何理由保存在test.xml
中?
答案 0 :(得分:1)
因此,由于您已创建DOMDocument
,因此可以使用DOMXpath。或继续使用getElementsByTagName()
您可以这样做(但仅限于此背景下):
$descriptions = $root->getElementsByTagName('description');
foreach($descriptions as $nodeDesciption)
{
$nodeDesciption->nodeValue ='Your custom value';
}