我的视图中有一个数据表,我需要在提交按钮上将值从datatable传递给controller。在文本框的情况下,它工作正常。我在从下拉列表和复选框传递值时遇到了麻烦。
我的观点旁边代码,
<script type="text/javascript" charset="utf-8">
$(document).ready(function () {
$.get(
'/Food/GetAllChild',
function (data) {
var htmlstmp = "";
for (var i = 0; i < data.length; i = i + 1) {
//Add rows to the datatable as per number of items in database
htmlstmp += "<tr>";
htmlstmp += " <td>";
htmlstmp += "<div class='divslno'><div class='tdlabel'>" + data[i].ChildId +"</div> </div>";
htmlstmp += "</td>";
htmlstmp += "<td><div class='divdeliveryitem'><select class='fordivdeliveryitemselector' id='" + data[i].ChildId + "'>";
htmlstmp += "<option class='foodlist'>Select</option>";
htmlstmp += "<option class='foodlist'>Menu 1</option>";
htmlstmp += "</select></div></td>";
htmlstmp += "<td>";
htmlstmp += "<div class='deliverystatusrow1'> <input type='checkbox' class='deliverystatuschb' value='false' /></div>";
htmlstmp += "</td>";
htmlstmp += "</tr>";
}
//Append "htmlstmp" to the datatable's tbody. childfoodattendancetbody is id of tbody
$('#childfoodattendancetbody').append(htmlstmp);
var oTable = $('#example').dataTable({
"iDisplayLength": 5,
"bSort": false
});
$("#btnsaveall").click(function () {
var datatopost = new Object();
$("#example .row_selected").each(function (i, item) {
var chidltdid = $(item).find("td .tdlabel:eq(0)").html();
datatopost["[" + i + "].ChildId"] = chidltdid;
datatopost["[" + i + "].FoodMenuId"] = $(item).find("td .fordivdeliveryitemselector#"+chidltdid+" :eq(1)").html();
datatopost["[" + i + "].FoodDelivery_Status"] = $(item).find("td .deliverystatuschb :eq(2)").attr("value");
});
});
$.ajax({
url: '@Url.Action("InsertData")',
type: 'POST',
traditional: true,
data: datatopost,
dataType: "html",
success: function (response) {
}
});
});
});
</script>
当我通过chrome检查元素
检查时,Datapost变量显示以下值[0].ChildId: "1"
[0].FoodDelivery_Status: undefined
[0].FoodMenuId: undefined
[1].ChildId: "2"
[1].FoodDelivery_Status: undefined
[1].FoodMenuId: undefined
我的行动看起来像,
[HttpPost]
public ActionResult InsertData(List<FoodDelivery> fooddelivery)
{
int _childid, _menu;
bool _deliverystatus;
for (int i = 0; i < fooddelivery.Count; i++)
{
_childid = fooddelivery[i].ChildId;
_deliverystatus = fooddelivery[i].FoodDelivery_Status;
_menu = fooddelivery[i].FoodMenuId;
// Code to insert to database
}
return View();
}
我在这里做错了什么?
请帮忙,
由于
答案 0 :(得分:3)
将表体渲染更改为razor syndax而不是Jquery,并为每个控件分配一个ID,以便更容易找到它的值。
试试这个
var selectValMenuItem = $('.fordivdeliveryitemselector#' + chidltdid + ' :selected').val();
var delvstatus = $('input[id=' + chidltdid+']').attr('checked');