我遇到了一些很好的问题答案,但这是关于从Hibernate 3.4.0GA升级到Hibernate 4.1.8的问题。所以这曾经在以前的版本下工作,我已经搜索了为什么它在这个新版本中突破的原因。
我得到了
org.hibernate.TransientObjectException:object引用未保存的瞬态实例 - 在刷新之前保存瞬态实例:com.test.server.domain.model.NoteItem.note - > com.test.server.domain.model.Note
任何帮助都会很棒。
这是我的课程。
@MappedSuperclass
public abstract class EntityBase implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
protected Long id;
@Version
@Column(name = "VERSION")
protected Long version;
public Long getId() {
return id;
}
public Long getVersion() {
return version;
}
protected static final EntityManager entityManager() {
return EntityManagerUtil.getEntityManager();
}
}
@Entity
@Table(name = "WORK_BOOK")
public class WorkBook extends EntityBase {
private static final long serialVersionUID = 1L;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "NOTE_ID")
private Note note;
public WorkBook() {
super();
}
public Note getNote() {
return note;
}
public void setNote(Note note) {
this.note = note;
}
public WorkBook persist() {
EntityManager em = entityManager();
EntityTransaction tx = em.getTransaction();
if (tx.isActive()) {
return em.merge(this);
} else {
tx.begin();
WorkBook saved = em.merge(this);
tx.commit();
return saved;
}
}
}
@Entity
@Table(name = "NOTE")
public class Note extends EntityBase {
private static final long serialVersionUID = 1L;
@OneToOne(mappedBy = "note")
private WorkBook workBook;
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "note")
private List<NoteItem> notes = new ArrayList<NoteItem>();
public WorkBook getWorkBook() {
return workBook;
}
public List<NoteItem> getNotes() {
return notes;
}
public void setWorkBook(WorkBook workBook) {
this.workBook = workBook;
}
public void setNotes(List<NoteItem> notes) {
if (notes != null) {
for (NoteItem ni : notes) {
ni.setNote(this);
}
}
this.notes = notes;
}
}
@Entity
@Table(name = "NOTE_ITEM")
public class NoteItem extends EntityBase {
private static final long serialVersionUID = 1L;
@Column(name = "NOTE_NAME")
private String noteName;
@Column(name = "NOTE_TEXT")
private String noteText;
@Column(name = "NOTE_DATE")
private Date noteDate;
@Column(name = "NOTE_CREATOR")
private String noteCreator;
@Column(name = "NOTE_CREATOR_ID")
private Integer noteCreatorId;
@ManyToOne
@JoinColumn(name = "NOTE_ID", updatable = true)
private Note note;
public String getNoteName() {
return noteName;
}
public void setNoteName(String noteName) {
this.noteName = noteName;
}
public String getNoteText() {
return noteText;
}
public void setNoteText(String noteText) {
this.noteText = noteText;
}
public Date getNoteDate() {
return noteDate;
}
public void setNoteDate(Date noteDate) {
this.noteDate = noteDate;
}
public String getNoteCreator() {
return noteCreator;
}
public void setNoteCreator(String noteCreator) {
this.noteCreator = noteCreator;
}
public Integer getNoteCreatorId() {
return noteCreatorId;
}
public void setNoteCreatorId(Integer noteCreatorId) {
this.noteCreatorId = noteCreatorId;
}
public Note getNote() {
return note;
}
public void setNote(Note note) {
this.note = note;
}
public NoteItem create() {
return new NoteItem();
}
}
答案 0 :(得分:31)
NoteItem
引用了之前必须保存的Note
的瞬态(尚未保存)实例。因此,请在属性说明中指定“Cascade.all”,或者先在Note上调用saveorupdate。
答案 1 :(得分:0)
在引入乐观锁定(@Version)后,所有PUT HTTP事务都面临相同的错误
在更新实体时,必须发送该实体的ID和版本。 如果任何实体字段与其他实体相关,那么我们也应该为该字段提供id和版本值,否则JPA会先尝试保留该相关实体
示例:我们有两个实体-> 车辆(id,汽车,版本); 汽车(ID,版本,品牌) 要更新/保留车辆实体,请确保车辆实体中的汽车字段提供了ID和版本字段