例如我有下表:
items
-----
item_id (usigned-int, not-null, auto-increment, primary)
created_at (datetime, not-null)
...
我有以下数据集:
(1, 01/01/2012)
(2, 03/01/2012)
(3, 07/01/2012)
(4, 12/01/2012)
(5, 28/01/2012)
(6, 02/02/2012)
(7, 06/02/2012)
(8, 13/02/2012)
(9, 27/02/2012)
我想得到以下结果:
(3, 07/01/2012)
(4, 12/01/2012)
(5, 28/01/2012)
(8, 13/02/2012)
(9, 27/02/2012)
即。每个月的每个第一(n = 2)条记录都会被跳过。
我如何通过MySQL实现这一目标?
答案 0 :(得分:1)
根据分区内项目的排名进行选择:
create table items (
item_id int,
created_at datetime
);
insert into items
select 1, '2012-01-01' union
select 2, '2012-01-03' union
select 3, '2012-01-07' union
select 4, '2012-01-12' union
select 5, '2012-01-28' union
select 6, '2012-02-02' union
select 7, '2012-02-06' union
select 8, '2012-02-13' union
select 9, '2012-02-28'
select i.*
from items i
join (
select t.item_id, count(item_id1) as row_no
from (
select t.item_id, t1.item_id as item_id1
from items t
join items t1 on t.item_id >= t1.item_id and
DATE_FORMAT(t.created_at, '%Y%m') = DATE_FORMAT(t1.created_at, '%Y%m')
) t
group by t.item_id
) g on i.item_id = g.item_id
where g.row_no > 2
答案 1 :(得分:1)
尝试此查询 -
SELECT id, created_at FROM (
SELECT t1.*, COUNT(*) r FROM items t1
LEFT JOIN items t2
ON MONTH(t2.created_at) = MONTH(t1.created_at) AND t2.id <= t1.id
GROUP BY
MONTH(t1.created_at), t1.id
) t
WHERE r > 2;
您还需要按年度过滤,或者只需添加年条件 -
SELECT id, created_at FROM (
SELECT t1.*, COUNT(*) r FROM items t1
LEFT JOIN items t2
ON YEAR(t2.created_at) = YEAR(t1.created_at) AND
MONTH(t2.created_at) = MONTH(t1.created_at) AND
t2.id <= t1.id
GROUP BY
YEAR(t1.created_at), MONTH(t1.created_at), t1.id
) t
WHERE r > 2;
答案 2 :(得分:0)
SELECT item_id, created_at,
CASE WHEN @month IN (RIGHT(created_at, 7), 0)
THEN @rownum := @rownum + 1
ELSE @rownum := 1 END AS rownum,
@month = RIGHT(created_at, 7) AS dummy
FROM ( SELECT item_id, created_at
FROM items
ORDER BY created_at DESC) AS h,
( SELECT @rownum := 0, @month := 0) AS vars
HAVING rownum > 2