我写了一个简单的程序。我尝试将选择结果存储在变量中。我使用“SELECT INTO”查询,但我不能这样做。
示例:
DECLARE
v_employeeRecord employee%ROWTYPE;
BEGIN
SELECT * INTO v_employeeRecord
FROM Employee WHERE Salary > 10;
END;
答案 0 :(得分:13)
你有几个选择。您可以将该查询转换为游标:
DECLARE
CURSOR v_employeeRecords IS
SELECT * FROM Employee WHERE Salary > 10;
v_employeeRecord employee%ROWTYPE;
BEGIN
FOR v_employeeRecord IN v_employeeRecords LOOP
/* Do something with v_employeeRecord */
END LOOP;
END;
或者,您可以创建TABLE
变量:
DECLARE
v_employeeRecord employee%ROWTYPE;
v_employeeRecords IS TABLE OF employee%ROWTYPE;
i BINARY_INTEGER;
BEGIN
SELECT * BULK COLLECT INTO v_employeeRecords
FROM Employee WHERE Salary > 10;
i := v_employeeRecords.FIRST;
WHILE v_employeeRecords.EXISTS(i) LOOP
v_employeeRecord := v_employeeRecords(i);
/* Do something with v_employeeRecord */
i := v_employeeRecords.NEXT(i);
END;
END;
我没有在Oracle中尝试过这些示例,因此您可能会遇到编译错误......
答案 1 :(得分:8)
如果您的SELECT返回多行,您将无法使用SELECT INTO synthax。
您需要构建一个循环来导航结果集:
Adam演示了如何使用显式游标和批量收集循环。我将展示如何构建最简单的循环(隐式游标,不需要DECLARE部分):
BEGIN
FOR c_emp IN (SELECT *
FROM Employee
WHERE Salary > 10) LOOP
/* do something with each row, for example:*/
UPDATE foo SET bar = bar + c_emp.salary WHERE id = c_emp.id;
END LOOP;
END;