我有一张产品表。我需要显示所有产品。我在不同条件下获取结果。
create table `products` (
`id` double ,
`category_id` double ,
`subcategory_id` double ,
`product_name` varchar (765),
`product_description` varchar (765),
`product_viewed` varchar (765),
`sale_wanted` tinyint (2),
`added_date` datetime ,
`updated_date` datetime ,
);
我需要像这样显示结果
1. The latest products (use of added date)
2. Most Wanted (Sorting by sale_wanted 1 for sale , 2 for wanted)
3. Most Viewed (Sorting by product_viewed)
4. Sorting by Specific Subcategory
所有结果都应以分页显示。如果我第一次得到结果,这没关系。但是,如果我使用分页链接,所有条件数据都会丢失,并且查询会在没有任何条件的情况下获取结果。我该如何处理这种情况。请我不需要Code我需要提示和建议。另一件事是我正在使用Codeigniter的分页类。
EDITED
这是我正在使用的模型方法
public function getProductsList($per_page=5,$page=0)
{
$info = $this->input->post();
if(isset($info['type']))
{
$type = $info['type'];
if($type == 'most_wanted'){
$where = " AND sale_wanted = 1";
$order_by = " ORDER BY ldc.added_date desc";
}else if($type == 'most_viewed'){
$where = " ";
$order_by = " ORDER BY ldc.product_viewed desc";
}else{
$where = " ";
$order_by = " ORDER BY ldc.added_date desc";
}
}else if(isset($info['sale_wanted']) AND isset($info['subcategory_id'])){
$sale_wanted = $info['sale_wanted'];
$subcategory_id = $info['subcategory_id'];
$where = " AND sale_wanted = $sale_wanted AND ldc.subcategory_id = $subcategory_id";
$order_by = " ORDER BY ldc.added_date desc";
}else if(isset($info['keyword'])){
$keyword = $info['keyword'];
$search_type = $info['search_type'];
$where = " AND ldc.$search_type like '$keyword%'";
$order_by = " ";
}else{
$where = " ";
$order_by = " ";
}
$num = 0;
if($page != 0){
$num = ($page * $per_page) - $per_page;
}
$sql_query = "
SELECT
ldc.id,
ldc.product_name,
ldc.product_viewed,
DATE_FORMAT(ldc.added_date, '%m/%d/%Y') as added_date,
ifnull(dc.name,'Unknown') as category,
dpi.product_image
FROM default_products AS ldc
LEFT JOIN default_manufacturers as dm ON dm.id = ldc.manufacturer
LEFT JOIN default_category as dc ON dc.category_id = ldc.category_id
LEFT JOIN ((select product_id , product_image from default_product_images group by product_id) as dpi)
ON dpi.product_id = ldc.id
WHERE approved = 1
$where
$order_by
LIMIT $num,$per_page
";
$query = $this->db->query($sql_query);
return $query->result();
}
答案 0 :(得分:1)
我强烈推荐这两个关于codeigniter分页的免费教程 -
视频教程,工作示例代码(可能需要将代码更新到CI 2.1),甚至评论中的一些有用信息。
Scratch的CodeIgniter:显示&对表格数据进行排序 http://net.tutsplus.com/tutorials/php/codeigniter-from-scratch-displaying-sorting-tabular-data/
Scratch的CodeIgniter:没有查询字符串的搜索结果 http://net.tutsplus.com/tutorials/php/codeigniter-from-scratch-search-results-without-query-strings-2/