Question

编辑：我已经成功地计算了我想要获得的值，但不是计算每行的值，而是计算一次并在任何地方发布该值。如何使用我的代码重新计算每一行？

图片：http://img515.imageshack.us/img515/9064/example2w.png

新守则：

<html>
<head>
<title>PHP-MySQL Project 4</title>

    <div align="center">
        <p>
            PHP-MySQL Project 4
        <br/>
            By: Ryan Strouse
        </p>
    </div>
</head>
<body bgcolor="#99FFFF">

<?php

$DBName = "surveys";
$DBConnect = @mysqli_connect("localhost", "students", "password")
    Or die("<p>Unable to connect to the database server.</p>"
    . "<p>Error code " . mysqli_connect_errno()
    . ": " . mysqli_connect_error()) . "</p>";

if (!$DBConnect)
    {
    echo "<p> The database server is not available.</p>";
    }
else
    {
    echo "<p> Successfully connected to the database $DBName</p>";
    }

mysqli_select_db($DBConnect, $DBName); 
echo "<p>Database -'$DBName'- found</p>";

$SQLstring = "SELECT * FROM surveys WHERE surveyCode = 'GEI001'";
$QueryResult = @mysqli_query($DBConnect, $SQLstring);
echo $SQLstring;
$row = mysqli_fetch_assoc($QueryResult);

$count_surveys = $row['surveyResponses'];

echo "<p>Total Responses: $count_surveys</p>";


$SQLstring2 = "SELECT * FROM results WHERE surveyCode = 'GEI001'";
$QueryResult2 = @mysqli_query($DBConnect, $SQLstring2);
echo $SQLstring2;
echo "<br/>";
$Row = mysqli_fetch_assoc($QueryResult2);


$SQLstring3 = "SELECT * FROM surveys, results";
$QueryResult3 = @mysqli_query($DBConnect, $SQLstring3);
$fetchrow = mysqli_fetch_assoc($QueryResult3);
$result_amount = (($fetchrow['resultResponses'] / $fetchrow['surveyResponses']) * 100);

echo "<table>";
echo "<tr><th>Commercial</th> <th>Views</th> <th>Percentage</th></tr>";
do {
    echo "<tr><td>{$Row['resultDescription']}</td>";
    echo "<td>{$Row['resultResponses']}</td>";
    echo "<td>$result_amount</td></tr>";
    $Row = mysqli_fetch_assoc($QueryResult3);
} while ($Row);
echo "</table>";


?>



<center>
<h3><a href="Survey1.html">Return To Main Page</a></h3>
<h3><a href="../Menu.html">Return to Menu</a></h3>
</center>
</body>

<footer>
<div align="center">
&copy; Copyright Ryan Strouse &copy;

</div>
</footer>
</html>

我有两个数据库表，我成功地将列数据拉入表中。表格的第三个单元格我想计算数据库中某些列的百分比。我不知道如何对此进行编码...我试图从另一个我发现没有运气的线程中提出SELECT语句中的内容。

以下是我正在努力开展工作的查询图片：http://img696.imageshack.us/img696/3862/examplegw.png

<html>
<head>
<title>PHP-MySQL Project 4</title>


</head>
<body bgcolor="#99FFFF">

<?php

$DBName = "surveys";
$DBConnect = @mysqli_connect("localhost", "students", "password")
    Or die("<p>Unable to connect to the database server.</p>"
    . "<p>Error code " . mysqli_connect_errno()
    . ": " . mysqli_connect_error()) . "</p>";

if (!$DBConnect)
    {
    echo "<p> The database server is not available.</p>";
    }
else
    {
    echo "<p> Successfully connected to the database $DBName</p>";
    }

mysqli_select_db($DBConnect, $DBName); 
echo "<p>Database -'$DBName'- found</p>";

$SQLstring = "SELECT * FROM surveys WHERE surveyCode = 'GEI001'";
$QueryResult = @mysqli_query($DBConnect, $SQLstring);
echo $SQLstring;
$row = mysqli_fetch_assoc($QueryResult);

$count_surveys = $row['surveyResponses'];

echo "<p>Total Responses: $count_surveys</p>";


$SQLstring2 = "SELECT * FROM results WHERE surveyCode = 'GEI001'";
$QueryResult2 = @mysqli_query($DBConnect, $SQLstring2);
echo $SQLstring2;
echo "<br/>";
$Row = mysqli_fetch_assoc($QueryResult2);


//this is where I am trying to calculate the value and then below it display in table 
//cell # 3
$SQLstring3 = "SELECT *,((resultResponses/surveyResponses)*100) AS AMOUNT FROM surveys, results";
$QueryResult3 = @mysqli_query($DBConnect, $SQLstring3);

do {
    echo "<table>";
    echo "<tr><th>Commercial</th> <th>Views</th> <th>Percentage</th></tr>";
    echo "<tr><td>{$Row['resultDescription']}</td>";
    echo "<td>{$Row['resultResponses']}</td>";
    echo "<td>$QueryResult3</td></tr>";
    $Row = mysqli_fetch_assoc($QueryResult);
} while ($Row);
echo "</table>";


?>



<center>
<h3><a href="Survey1.html">Return To Main Page</a></h3>
<h3><a href="../Menu.html">Return to Menu</a></h3>
</center>
</body>

<footer>

</footer>
</html>

Answer 1

IF 我理解您的要求，您可能正在尝试计算在MySQL查询结果中可以找到的值的百分比。如果是这样，那么我将使用函数mysql_num_rows来获取记录的总数，然后在while和if我有一个计数器，我有多少次满足这个价值。

然后你只做简单的数学运算，例如：

result = (100 * counter) / mysql_num_rows

并且有一个百分比。然后你只需要echo结果，无论你想要什么！：）

我希望我能正确理解你的问题！

Answer 2

$result = mysql_query("SELECT yourRow FROM yourTable");
$aArray = array();
$cont=0;
while($col = mysql_fetch_assoc($result){
   $aArray[$cont] = $col['yourRow'];
   cont++;
}

这应该为你提供一个可行的数组，让你用它来计算，然后回应它。干杯

从数据库计算列然后拉入表格单元格

2 个答案: