Question

如何为不同的JButton使用相同的ActionPerformed函数提供不同的功能？

public class ToolBarExample extends JPanel implements ActionListener  {

public JTextPane pane;
public JMenuBar menuBar;
public JToolBar toolBar;

public JButton Aster;
public JButton Azaleas;
public JButton ChristFern;
public JButton JapBarberry;

public ToolBarExample() {

    toolBar = new JToolBar("Formatting", JToolBar.VERTICAL);

    this.Aster = new JButton(new ImageIcon("images/PlantIcons/[Blueprint]_Aster.png"));
    this.toolBar.add(Aster);    
    this.Aster.addActionListener(this);
    this.Azaleas = new JButton(new ImageIcon("images/PlantIcons/[Blueprint]_Azaleas.png"));
    this.toolBar.add(Azaleas);
    this.Azaleas.addActionListener(this);
    this.ChristFern = new JButton(new ImageIcon("images/PlantIcons/[Blueprint]_ChristmasFern.png"));
    this.toolBar.add(ChristFern);
    this.ChristFern.addActionListener(this);
    this.JapBarberry = new JButton(new ImageIcon("images/PlantIcons/[Blueprint]_JapaneseBarberry.png"));
    this.toolBar.add(JapBarberry);
    this.JapBarberry.addActionListener(this);
}

public void actionPerformed(ActionEvent e) {
        try {
            if(e.getSource() == Aster) {
                NativePlant plant1 = new NativePlant(4, 5, 600, "test", "images/[Blueprint]_Aster.png", 200, 600);
                Game.setNatives(plant1);
            }

            if(e.getSource() == Azaleas) {
                NativePlant plant1 = new NativePlant(4, 5, 600, "test", "images/[Blueprint]_Azaleas.png", 100, 600);
                Game.setNatives(plant1);
            }
            if(e.getSource() == ChristFern) {
                NativePlant plant1 = new NativePlant(4, 5, 600, "test", "images/[Blueprint]_ChristmasFern.png", 300, 600);
                Game.setNatives(plant1);
            }
            if(e.getSource() == JapBarberry) {
                NativePlant plant1 = new NativePlant(4, 5, 600, "test", "images/[Blueprint]_JapaneseBarberry.png", 400, 600);
                Game.setNatives(plant1);
            }
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }
}

现在我正在尝试使用e.getSource来查找正在推送的按钮，然后为每个按钮执行不同的操作。但是，现在唯一正在工作的按钮是第一个（Aster）。

有谁知道我做错了什么，或者我应该做什么？

Answer 1

您可以使用每个按钮的setActionCommand（）并从actionPerformed中调用相应的getActionCommand。在我看来，使用常量来定义动作将是一个很好的方法。一小部分样本如下;

public class SwingTest extends JFrame implements ActionListener{

public SwingTest()
{
    JButton btnOne = new JButton("test one");
    btnOne.addActionListener(this);
    btnOne.setActionCommand("TestOne");
    JButton btnTwo = new JButton("test two");
    btnTwo.addActionListener(this);
    btnTwo.setActionCommand("TestTwo");

    this.setLayout(new FlowLayout());
    this.getContentPane().add(btnOne);
    this.getContentPane().add(btnTwo);
}

public static void main(String[] args) {
    SwingTest t = new SwingTest();
    t.pack();
    t.setVisible(true);
}

@Override
public void actionPerformed(ActionEvent e) {

    System.out.println(e.getActionCommand());
}
}

Answer 2

而不是

e.getSource() == Aster

将其更改为：

e.getSource().equals(Aster)

它看起来像是一样的东西，但它会给你你想要的结果...... 因为.equals（）正在检查对象的状态，而'=='正在检查实际的实例。

http://www.javabeat.net/qna/13-what-is-difference-between-equals-and-/

如何为JButtons提供不同的功能？

2 个答案: