Question

我的查询结果如下：

+---------------+------+------+------+------+------+------+------+-------+
| order_main_id | S36  | S37  | S38  | S39  | S40  | S41  | S42  | total |
+---------------+------+------+------+------+------+------+------+-------+
|            26 |  127 |  247 |  335 |  333 |  223 |  111 |   18 |  1394 | 
|            26 |  323 |  606 |  772 |  765 |  573 |  312 |  154 |  3505 | 
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 | 
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 | 
|            39 |   65 |   86 |   86 |   42 |   21 | NULL | NULL |   300 | 
|            39 |   42 |   58 |   58 |   28 |   14 | NULL | NULL |   200 | 
|            35 |   11 |   20 |   21 |   18 |    9 |    2 | NULL |    81 | 
|            35 |   10 |   25 |   30 |   23 |   12 |    1 | NULL |   101 | 
+---------------+------+------+------+------+------+------+------+-------+

我想在输入不同的order_main_id之前插入SUM，就像这样的结果：

+---------------+------+------+------+------+------+------+------+-------+
| order_main_id | S36  | S37  | S38  | S39  | S40  | S41  | S42  | total |
+---------------+------+------+------+------+------+------+------+-------+
|            26 |  127 |  247 |  335 |  333 |  223 |  111 |   18 |  1394 | 
|            26 |  323 |  606 |  772 |  765 |  573 |  312 |  154 |  3505 |
|               |  450 |  853 | 1107 | 1098 |  796 |  423 |  172 |  4899 | 
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 | 
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 |
|               |   50 |   70 |   70 |   70 |   40 | NULL | NULL |   300 | 
|            39 |   65 |   86 |   86 |   42 |   21 | NULL | NULL |   300 | 
|            39 |   42 |   58 |   58 |   28 |   14 | NULL | NULL |   200 |
|               |  107 |  144 |  144 |   70 |   35 | NULL | NULL |   500 | 
|            35 |   11 |   20 |   21 |   18 |    9 |    2 | NULL |    81 | 
|            35 |   10 |   25 |   30 |   23 |   12 |    1 | NULL |   101 |
|               |   21 |   45 |   51 |   41 |   21 |    3 | NULL |   182 | 
+---------------+------+------+------+------+------+------+------+-------+

如何实现这一目标？

Answer 1

您需要编写第二个Query，它使用GROUP BY order_main_id。

类似的东西：

SELECT sum(S41+...) FROM yourTable GROUP BY orderMainId

ķ

Answer 2

您实际上可以在一个查询中执行此操作，但使用union all（实际上是两个查询，但结果集合在一起以生成一个非常棒的结果集）：

select
    order_main_id,
    S36,
    S37,
    S38,
    S39,
    S40,
    S41,
    S42,
    S36 + S37 + S38 + S39 + S40 + S41 + S42 as total,
    'Detail' as rowtype
from
    tblA
union all
select
    order_main_id,
    sum(S36),
    sum(S37),
    sum(S38),
    sum(S39),
    sum(S40),
    sum(S41),
    sum(S42),
    sum(S36 + S37 + S38 + S39 + S40 + S41 + S42),
    'Summary' as rowtype
from
    tblA
group by
    order_main_id
order by
    order_main_id, RowType

请记住，order by会影响union all的整体，而不仅仅是最后一个查询。所以，你的结果集看起来像这样：

+---------------+------+------+------+------+------+------+------+-------+---------+
| order_main_id | S36  | S37  | S38  | S39  | S40  | S41  | S42  | total | rowtype |
+---------------+------+------+------+------+------+------+------+-------+---------+
|            26 |  127 |  247 |  335 |  333 |  223 |  111 |   18 |  1394 | Detail  |
|            26 |  323 |  606 |  772 |  765 |  573 |  312 |  154 |  3505 | Detail  |
|            26 |  450 |  853 | 1107 | 1098 |  796 |  423 |  172 |  4899 | Summary |
|            35 |   11 |   20 |   21 |   18 |    9 |    2 | NULL |    81 | Detail  |
|            35 |   10 |   25 |   30 |   23 |   12 |    1 | NULL |   101 | Detail  |
|            35 |   21 |   45 |   51 |   41 |   21 |    3 | NULL |   182 | Summary |
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 | Detail  |
|            38 |   25 |   35 |   35 |   35 |   20 | NULL | NULL |   150 | Detail  |
|            38 |   50 |   70 |   70 |   70 |   40 | NULL | NULL |   300 | Summary |
|            39 |   65 |   86 |   86 |   42 |   21 | NULL | NULL |   300 | Detail  |
|            39 |   42 |   58 |   58 |   28 |   14 | NULL | NULL |   200 | Detail  |
|            39 |  107 |  144 |  144 |   70 |   35 | NULL | NULL |   500 | Summary |
+---------------+------+------+------+------+------+------+------+-------+---------+

这样，您就知道什么是什么，什么不是详细信息或摘要行，以及它的order_main_id。您可以随时（也可能应该）在表示层中隐藏此列。

Answer 3

对于类似这样的事情，我认为您应该使用报告库（例如Crystal Reports），这样可以省去很多麻烦，请查看JasperReports and similar projects on osalt

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