更新:我发现了这个错误。由于我之前发布的代码非常复杂,我简化了它们,只在出现问题时才保留该部分。
if (number >= dim * num_points)
return;
但实际上,我只有num_points,我想使用num_points线程,所以正确的方法应该是
if (number >= num_points)
return;
谢谢大家的帮助。
我正在从CPU到GPU重写一些C ++代码。代码粘贴在下面。对不起,这很长,因为我觉得这样的问题更容易被发现。
在代码中,对于每个线程我都需要一些矩阵格式的中间结果,所以我为这些中间结果分配设备内存,例如d_dir2,d_R,d_Stick,d_PStick。结果证明不是我所期望的,所以为了调试,我试图以这种方式输出一些中间结果R:
if (k == 0) { results[tmp_int1 + i * dim + j] = R[tmp_int1 + i * dim + j]; }
以后在C ++中,我打印结果。 但是,我发现结果每次都会给出不同的值。有时它会给出正确的答案R,有时是PStick的值,有时是R和PStick的组合,有时是R和0的组合(结果在开始时初始化为0)。
我很困惑是什么导致了这个问题。任何的想法?非常感谢你:))
__global__ void stickvote(const int dim, const int num_points, const int gridx, float Sigma, float* input, float* dir2, float* R, float* Stick, float* PStick, float* results) {
float threshold = 4 * Sigma;
float c = (- 16 * log(0.1f) * (sqrt(Sigma) - 1)) / 3.1415926f / 3.1415926f;
int row = blockIdx.y * blockDim.y + threadIdx.y;
int col = blockIdx.x * blockDim.x + threadIdx.x;
int number = row * BLOCK_SIZE * gridx + col;
if (number >= dim * num_points) //// The bug is here!
return;
}
extern "C" void KernelStickVote(int dim, int num_points, float Sigma, float* input, float* results) {
const int totalpoints = num_points;
const int totalpoints_input = (dim + 1)* (dim + 1) * num_points;
const int totalpoints_output = dim * dim * num_points;
size_t size_input = totalpoints_input * sizeof(float);
size_t size_output = totalpoints_output * sizeof(float);
float* d_input;
cutilSafeCall(cudaMalloc((void**)&d_input, size_input));
float* d_result;
cutilSafeCall(cudaMalloc((void**)&d_result, size_output));
// used to save dir, and calculate dir * dir'
float* d_dir2;
cutilSafeCall(cudaMalloc((void**)&d_dir2, dim * num_points * sizeof(float)));
// used to save R: dim * dim * N
float* d_R;
cutilSafeCall(cudaMalloc((void**)&d_R, size_output));
// used to save Stick: dim * dim * N
float* d_Stick;
cutilSafeCall(cudaMalloc((void**)&d_Stick, size_output));
// used to save Stick: dim * dim * N
float* d_PStick;
cutilSafeCall(cudaMalloc((void**)&d_PStick, size_output));
// Copy input data from host to device
cudaMemcpy(d_input, input, size_input, cudaMemcpyHostToDevice);
int totalblock = (totalpoints % BLOCKPOINTS==0 ? totalpoints/BLOCKPOINTS : (int(totalpoints/BLOCKPOINTS) + 1));
int gridx = (65535 < totalblock ? 65535 : totalblock);
int gridy = (totalblock % gridx == 0 ? totalblock/gridx : (int(totalblock/gridx)+1) );
dim3 dimBlock(BLOCK_SIZE, BLOCK_SIZE);
dim3 dimGrid(gridx, gridy);
stickvote<<<dimGrid, dimBlock>>>(dim, num_points, gridx, Sigma, d_input, d_dir2, d_R, d_Stick, d_PStick, d_result);
cudaMemcpy(results, d_result, size_output, cudaMemcpyDeviceToHost);
cudaFree(d_input);
cudaFree(d_result);
cudaFree(d_dir2);
cudaFree(d_R);
cudaFree(d_Stick);
cudaFree(d_PStick);
}
答案 0 :(得分:1)
该问题的原始海报进行了一些进一步的代码简化和调试他/她自己并发现内核中的guard语句:
if (number >= dim * num_points)
return;
事实上,是不正确的,应该是
if (number >= num_points)
return;
这是错误的来源。
此答案已添加为社区维基解答,目的是从未答复的队列中删除此问题。