我想从Android中的联系方式获取电子邮件地址和电话号码。我能够接听电话号码,但我希望当它的选择电话号码时,它也是相应的联系人ID的电子邮件地址。所以我可以添加它在arraylist。 感谢
public void getContactslist()
{
ContentResolver contactResolver = getContentResolver();
Cursor cursor = contactResolver.query(Phone.CONTENT_URI , null,null,null, null);
// Cursor emails = contactResolver.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,null, null, null);
if(cursor.getCount() > 0)
{
cursor.moveToFirst();
do {
String number = cursor.getString(cursor.getColumnIndex(Phone.NUMBER));
String displayname = cursor.getString(cursor.getColumnIndex(Phone.DISPLAY_NAME));
long contactid = cursor.getLong(cursor.getColumnIndex(Phone.CONTACT_ID));
Cursor emails = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = " + contactid, null, null);
System.out.println("**emails*******"+number);
while (emails.moveToNext())
{
String email = emails.getString(emails.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
Log.e("Email", email);
}
}while (cursor.moveToNext() );
}
}
答案 0 :(得分:0)
我尝试了下面的代码片段,但它确实有用。希望这会对你有所帮助。
public HashMap<String, String> getNameEmailDetails(){
HashMap<String, String> names = new HashMap<String, String>();
ContentResolver cr = getContext().getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
Cursor cur1 = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
new String[]{id}, null);
while (cur1.moveToNext()) {
//to get the contact names
String name=cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
Log.e("Name :", name);
String email = cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
Log.e("Email", email);
if(email!=null){
names.put(name, email);
}
}
cur1.close();
}
}
return names;
}