Question

我在xsl上工作，将思维导图文件转换为csv树结构。我使用python lxml

还有一个小问题 - 如何省略模板中必需的根标签？将它们留下结果：

AssertionError: ElementTree not initialized, missing root

源xml

<map version="0.9.0">

<node TEXT="Familie">
<node TEXT="Kinder">
<node TEXT="Sohn">
</node>

<node TEXT="Tochter">
<node TEXT="Hobbies">
<node TEXT="Fu&#xdf;ball">
</node>
</node>
</node>

</node>
</node>
</map>

输出。注意 p 标签。如何放弃它们？

<p>,"Familie"
  "Familie","Kinder"
  "Familie","Kinder","Sohn"
  "Familie","Kinder","Tochter"
  "Familie","Kinder","Tochter","Hobbies"
  "Familie","Kinder","Tochter","Hobbies","Fu&#223;ball"
  </p>

我的表

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="no" encoding="ISO-8859-1" omit-xml-declaration="yes" media-type="string"/>
<xsl:strip-space elements="*" />

  <xsl:template match="/">
    <p>
      <xsl:apply-templates/>
    </p>
  </xsl:template>

<xsl:template match="node">
  <xsl:param name="par"/>
  <xsl:variable name="nodetext" select="@TEXT"/>
  <xsl:variable name="depth" select="count(ancestor::*)"/>
<xsl:value-of select="$par"/>,&quot;<xsl:value-of select="$nodetext"/>&quot;
  <xsl:choose>

    <xsl:when test="$depth&lt;2">
      <xsl:apply-templates>
        <xsl:with-param name="par" select="concat('&quot;',$nodetext,'&quot;')"/>
      </xsl:apply-templates>
    </xsl:when>

    <xsl:otherwise>
      <xsl:apply-templates>
        <xsl:with-param name="par" select="concat($par,',&quot;',$nodetext,'&quot;')"/>
      </xsl:apply-templates>
    </xsl:otherwise>

  </xsl:choose>

</xsl:template>

</xsl:stylesheet>

Answer 1

更改此模板：

<xsl:template match="/">
  <p>
    <xsl:apply-templates/>
  </p>
</xsl:template>

......对此：

<xsl:template match="/">
  <xsl:apply-templates/>
</xsl:template>

Answer 2

我无法重复报告结果 - 使用Saxon 6.5.4我：

,"Familie"
  "Familie","Kinder"
  "Familie","Kinder","Sohn"
  "Familie","Kinder","Tochter"
  "Familie","Kinder","Tochter","Hobbies"
  "Familie","Kinder","Tochter","Hobbies","Fuޢall"

任何兼容的XSLT处理器都应该尊重<xsl:output method="text"/>并生成纯文本输出。

无论如何，如果您不想生成任何元素，请将其从转换中删除：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="no" encoding="ISO-8859-1" omit-xml-declaration="yes" media-type="string"/>
<xsl:strip-space elements="*" />

  <xsl:template match="/">
      <xsl:apply-templates/>
  </xsl:template>

<xsl:template match="node">
  <xsl:param name="par"/>

  <xsl:variable name="nodetext" select="@TEXT"/>
  <xsl:variable name="depth" select="count(ancestor::*)"/>

  <xsl:value-of select="$par"/>,&quot;<xsl:value-of select="$nodetext"/>&quot;

  <xsl:choose>
    <xsl:when test="$depth&lt;2">
      <xsl:apply-templates>
        <xsl:with-param name="par" select="concat('&quot;',$nodetext,'&quot;')"/>
      </xsl:apply-templates>
    </xsl:when>

    <xsl:otherwise>
      <xsl:apply-templates>
        <xsl:with-param name="par" select="concat($par,',&quot;',$nodetext,'&quot;')"/>
      </xsl:apply-templates>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>
</xsl:stylesheet>

xslt模板根标签，在文本输出中省略

2 个答案: