在谷歌电子表格中,行数减一

时间:2012-11-18 10:06:31

标签: google-apps-script google-docs-api

我想删除空行。第885行是非空行,应保留。但是,我的代码说(并在msgbox中显示)885为空,应该删除。当它到达i = 884时,它会打印第885行中的内容,并表示不会删除它。所以,我很困惑。它似乎正确地对数据采取行动,但它报告错误的行号。我怀疑你会告诉我偏移是零基础,行从1开始,所以如果lastrow = 888(基于1),那么我需要减去1来匹配偏移量。所以我在电子表格中看到的行885实际上是第884行作为偏移量。

但......当i =第885行有数据时,偏移量为884.当i = 884时,偏移量为883 ...所以为什么要打印第885行?在这里严重困惑。我错了什么?

最后但最重要的是......它正在删除错误的行!如何引用正确的数据,但仍然删除错误的行???

var s = SpreadsheetApp.getActiveSheet();
var range = SpreadsheetApp.getActiveSheet().getDataRange();
var i = range.getLastRow();
var msg;
var colNum;

for (; i > 1; i--) {  // I like to start at the end
  var foundAvalue=0;  // reset flag for each row

  rowRange = range.offset(i, 0, 1); 

  var valArray=rowRange.getValues();
  var foundAvalue=0;
  var msg;
  var totalColumns=rowRange.getNumColumns();

   colNum=0;   

   while (colNum < totalColumns && (foundAvalue==0)) {
     if (valArray[0][colNum] != '') {       
       foundAvalue=1; 
       msg="Row " + i + " =" + valArray[0];
       Browser.msgBox(msg);
       msg="Row " + i + " will not be deleted";
       Browser.msgBox(msg);
     }
     colNum++;
   }
   if (foundAvalue == 0) {
      msg="Row " + i + " =" + valArray[0] + "WILL be deleted";
      Browser.msgBox(msg);
           // delete empty row
      // s.deleteRow(i);
   }

 } // end for(i)  

2 个答案:

答案 0 :(得分:3)

下面是一些应该完成你想要的代码。你是正确的,因为问题的根源在于基于0的索引。棘手的部分是JavaScript / Apps脚本数组使用基于0的索引,但是当您调用getLastRow()之类的内容时,返回的范围是从1开始的。总而言之,你的代码很好 - 只有这个问题才能让你沮丧。希望这会有所帮助:

function DeleteFun(){
  var mySheet = SpreadsheetApp.getActiveSheet();
  var range = mySheet.getDataRange();

  // Iterate using a counter, starting at the last row and stopping at
  // the header (assumes the header is in the first row)
  for (i = mySheet.getLastRow() - 1; i > 0; i--) {
    var foundAvalue = 0;
    // Here we get the values for the current row and store in an array
    rowRange = range.getValues()[i]
    // Now we iterate through that array
    for (j = 0; j <= rowRange.length; j++) {
      // If any non-nulls are found, alert they won't be deleted and move on
      if (rowRange[j] != null && rowRange[j] != '') {
        foundAvalue = 1; 
        msg="Row " + (i+1) + " =" + rowRange[0] + " and will not be deleted";
        Browser.msgBox(msg);
        break;
       }
    }

    if (foundAvalue == 0) {
      msg="Row " + (i+1) + " =" + rowRange[0] + "WILL be deleted";
      Browser.msgBox(msg);
      // Delete empty row
      mySheet.deleteRow(i+1);
    }
  }
}

答案 1 :(得分:1)

如果您不在工作表中使用公式,也可以在“纯”数组中执行此操作。

就像这样:

function deleteEmptyRows(){ 
 var sh = SpreadsheetApp.getActiveSheet();
 var data = sh.getDataRange().getValues();
 var targetData = new Array();
 for(n=0;n<data.length;++n){
 if(data[n].join().replace(/,/g,'')!=''){ targetData.push(data[n])};// checks the whole row
 Logger.log(data[n].join().replace(/,/g,''))
 }
 sh.getDataRange().clear(); // clear the whole sheet
 sh.getRange(1,1,targetData.length,targetData[0].length).setValues(targetData);//write back all non empty rows
 }