对于我的项目,我必须将整数转换为字节数组并将字节数组转换回整数。 我做了以下代码,但它无法正常工作
int temp=200;
byte[] tempbyte= new byte[4];
String s= String.valueOf(temp);
tempbyte= s.getBytes(); // integer to byte array conversion
String s2 = String.valueOf(ByteBuffer.wrap(tempbyte).getInt());
int temp2 = Integer.parseInt(s2); // byte array to integer conversion
System.out.println("the value of temp2 = "+temp2);
答案 0 :(得分:2)
尝试这样的事情: -
byte[] arr = { 0x00, 0x01 };
ByteBuffer wrapped = ByteBuffer.wrap(arr);
short num = wrapped.getShort();
ByteBuffer dbuf = ByteBuffer.allocate(2);
dbuf.putShort(num);
byte[] bytes = dbuf.array();
使用java.nio
命名空间
答案 1 :(得分:1)
论文是我多年前制作的可以帮助你的功能:
public static float byteArrayToFloat(byte[] p_bArray)
{
int nValue;
nValue = (0xFF & p_bArray[0]);
nValue = nValue | ((0xFF & p_bArray[1]) << 8);
nValue = nValue | ((0xFF & p_bArray[2]) << 16);
nValue = nValue | ((0xFF & p_bArray[3]) << 24);
float fValue = Float.intBitsToFloat(nValue);
return fValue;
}
public static byte[] floatToByteArray(float p_fValue)
{
byte [] bArray = new byte[4];
int nValue;
nValue = Float.floatToIntBits(p_fValue);
bArray[0] = (byte)nValue;
bArray[1] = (byte)(nValue >> 8);
bArray[2] = (byte)(nValue >> 16);
bArray[3] = (byte)(nValue >> 24);
return bArray;
}
public static double byteArrayToDouble(byte[] p_bArray)
{
long lValue;
lValue = (long)p_bArray[0] & 0xFF;
lValue = lValue | (((long)p_bArray[1] & 0xFF) << 8);
lValue = lValue | (((long)p_bArray[2] & 0xFF) << 16);
lValue = lValue | (((long)p_bArray[3] & 0xFF) << 24);
lValue = lValue | (((long)p_bArray[4] & 0xFF) << 32);
lValue = lValue | (((long)p_bArray[5] & 0xFF) << 40);
lValue = lValue | (((long)p_bArray[6] & 0xFF) << 48);
lValue = lValue | (((long)p_bArray[7] & 0xFF) << 56);
double dValue = Double.longBitsToDouble(lValue);
return dValue;
}
public static byte[] doubleToByteArray(double p_dValue)
{
byte [] bArray = new byte[8];
long lValue;
lValue = Double.doubleToLongBits(p_dValue);
bArray[0] = (byte)lValue;
bArray[1] = (byte)(lValue >> 8);
bArray[2] = (byte)(lValue >> 16);
bArray[3] = (byte)(lValue >> 24);
bArray[4] = (byte)(lValue >> 32);
bArray[5] = (byte)(lValue >> 40);
bArray[6] = (byte)(lValue >> 48);
bArray[7] = (byte)(lValue >> 56);
return bArray;
}
public static int byteArrayToInt(byte[] p_bArray)
{
int nValue;
nValue = ((int)p_bArray[0]) & 0x000000FF;
nValue = nValue | (((int)p_bArray[1] & 0x000000FF) << 8);
nValue = nValue | (((int)p_bArray[2] & 0x000000FF) << 16);
nValue = nValue | (((int)p_bArray[3] & 0x000000FF) << 24);
return nValue;
}
public static byte[] intToByteArray(int p_nValue)
{
byte [] bArray = new byte[4];
bArray[0] = (byte)p_nValue;
bArray[1] = (byte)(p_nValue >> 8);
bArray[2] = (byte)(p_nValue >> 16);
bArray[3] = (byte)(p_nValue >> 24);
return bArray;
}
答案 2 :(得分:0)
我的版本:
int i = 1;
byte[] bytes = BigInteger.valueOf(i).toByteArray();
i = new BigInteger(bytes).intValue();
答案 3 :(得分:0)
Integer类有一个将数字转换为字节表示的方法。
String i = Integer.toBinaryString(4);
你也可以反之亦然
String binaryString = "100";
int base = 2;
int decimal = Integer.parseInt(binaryString, base);