Question

可能重复：
How to display the record with the highest value in Oracle?

我应该从数据库中显示最老的人的姓名和年龄。我使用的代码显示了几个人的姓名和计算年龄，但它不会显示单个最老的人。我如何让它工作？这是我的代码

select dr_drvname as "Name", trunc(max((sysdate-dr_brthdate)/365)) as "Highest AGE"
from driver,dual
group by dr_drvname;

Answer 1

Oracle的另一种方式是：

SELECT
    dr_drvname AS "Name",
    trunc(months_between(sysdate, dr_birthdate) / 12) AS "Highest Age"
FROM
(
SELECT
    dr_drvname,
    dr_birthdate
FROM
    driver
ORDER BY
    dr_birthdate
)
WHERE
    ROWNUM = 1;

Answer 2

尝试这样的事情：

SELECT top 1
  Firstname, LastName, Max([BirthDate]) as Oldest    
  FROM [Employees]
  group by BirthDate, FirstName, LastName

注意：如果多人有相同的出生日期，有哪些要求？

Answer 3

您可以使用分析函数

select dr_drvname as "Name", 
       trunc( months_between( sysdate, dr_birthdate )/ 12 ) "Highest Age"
  from (select dr_drvname ,
               dr_birthdate,
               rank() over (order by dr_birthdate) rnk
          from driver)
 where rnk = 1;

显示名称和最大年龄

3 个答案: