Question

我的表'store'中有4个colums - id，store_name，lat，lng。我希望显示半径为30英里的所有结果。我明白了：

$lat = '25.7742644';
$lng = '-80.1936558';
$miles = 30;

$query = mysql_query("SELECT *, 
           ( 3959 * acos( cos( radians($lat) ) 
           * cos( radians( lat ) ) 
           * cos( radians( lng ) - radians($lng) ) 
           + sin( radians($lat) ) 
           * sin( radians( lat ) ) ) ) AS distance 
        FROM stores
        HAVING distance < $miles 
        ORDER BY distance 
        LIMIT 0, 20 ");
    $result = mysql_query($query) or die(mysql_error());
    while($row=mysql_fetch_array($result)) {


    echo $store_name;



    }

但是当我启动脚本时，我得到“查询为空”？

Answer 1

$query = mysql_query("SELECT *, ...")
^^^^^^   ^^^^^^^^^^^

$result = mysql_query($query) or die(mysql_error());
          ^^^^^^^^^^^ ^^^^^^

摆脱其中一个mysql_query。

Answer 2

试试这个：

<?php

$lng = '-80.1936558';
$lat = '25.7742644';
$miles = 30;

$query = "SELECT *, 
( 3959 * acos( cos( radians('$lat') ) * 
cos( radians( latitude ) ) * 
cos( radians( lnggitude ) - 
radians('$lng') ) + 
sin( radians('$lat') ) * 
sin( radians( latitude ) ) ) ) 
AS distance FROM yourtable HAVING distance < '$miles' ORDER BY distance ASC LIMIT 0, 20";
$result = mysql_query($query) or die(mysql_error());
while($row=mysql_fetch_array($result)){
  echo $row["store_name"] . "<br />";
}

?>

Tutorial link.

查询为空

2 个答案: