照片正在旋转90度,同时从三星移动其他手机(HTC)的摄像头捕捉它的工作正常。请帮助我。
Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(cameraIntent, IMAGE_CAPTURE);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
try
{
if (requestCode == IMAGE_CAPTURE) {
if (resultCode == RESULT_OK){
Uri contentUri = data.getData();
if(contentUri!=null)
{
String[] proj = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(contentUri, proj, null, null, null);
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
imageUri = Uri.parse(cursor.getString(column_index));
}
tempBitmap = (Bitmap) data.getExtras().get("data");
mainImageView.setImageBitmap(tempBitmap);
isCaptureFromCamera = true;
}
}
答案 0 :(得分:11)
某些设备根据设备方向旋转图像。
这里我写了一个常用的方法来获得方向并以正确的比例获得图像
public Bitmap decodeFile(String path) {//you can provide file path here
int orientation;
try {
if (path == null) {
return null;
}
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
// Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE = 70;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 0;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 2;
height_tmp /= 2;
scale++;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
Bitmap bm = BitmapFactory.decodeFile(path, o2);
Bitmap bitmap = bm;
ExifInterface exif = new ExifInterface(path);
orientation = exif
.getAttributeInt(ExifInterface.TAG_ORIENTATION, 1);
Log.e("ExifInteface .........", "rotation ="+orientation);
// exif.setAttribute(ExifInterface.ORIENTATION_ROTATE_90, 90);
Log.e("orientation", "" + orientation);
Matrix m = new Matrix();
if ((orientation == ExifInterface.ORIENTATION_ROTATE_180)) {
m.postRotate(180);
// m.postScale((float) bm.getWidth(), (float) bm.getHeight());
// if(m.preRotate(90)){
Log.e("in orientation", "" + orientation);
bitmap = Bitmap.createBitmap(bm, 0, 0, bm.getWidth(),
bm.getHeight(), m, true);
return bitmap;
} else if (orientation == ExifInterface.ORIENTATION_ROTATE_90) {
m.postRotate(90);
Log.e("in orientation", "" + orientation);
bitmap = Bitmap.createBitmap(bm, 0, 0, bm.getWidth(),
bm.getHeight(), m, true);
return bitmap;
}
else if (orientation == ExifInterface.ORIENTATION_ROTATE_270) {
m.postRotate(270);
Log.e("in orientation", "" + orientation);
bitmap = Bitmap.createBitmap(bm, 0, 0, bm.getWidth(),
bm.getHeight(), m, true);
return bitmap;
}
return bitmap;
} catch (Exception e) {
return null;
}
}
修改强>
此代码未经过优化,我只显示了我的测试项目中的逻辑代码。
答案 1 :(得分:2)
您可以添加到上述解决方案的另一件事是"samsung".contentEquals(Build.MANUFACTURER)
。如果您知道问题仅适用于三星设备,则您可以合理地确定需要旋转返回的图像(仅限)if ("samsung".contentEquals(Build.MANUFACTURER) && getActivity().getRequestedOrientation() == ActivityInfo.SCREEN_ORIENTATION_SENSOR_PORTRAIT // && width > height//) // here you know you need to rotate
你可以合理地&#34;确信旋转是有保证的。
答案 2 :(得分:0)
public static Bitmap rotateBitmap(Bitmap b, float degrees) {
Matrix m = new Matrix();
if (degrees != 0) {
// clockwise
m.postRotate(degrees, (float) b.getWidth() / 2,
(float) b.getHeight() / 2);
}
try {
Bitmap b2 = Bitmap.createBitmap(b, 0, 0, b.getWidth(),
b.getHeight(), m, true);
if (b != b2) {
b.recycle();
b = b2;
}
} catch (OutOfMemoryError ex) {
// We have no memory to rotate. Return the original bitmap.
}
return b;
}
答案 3 :(得分:0)
如果它确实是一个错误,那么您可能需要手动将其旋转回横向。位图数据始终具有宽度和高度,只需看一下数字,如果宽度小于高度,则根据alistair3408的答案旋转图像。