我使用自己的域名在Google网站上创建了一个网站。单击like按钮（生成steegle.com）会出现错误：“抱歉，此帖子包含可疑URL：未知错误”。关于如何修复这个或更好的代码的任何想法？
这是生成/使用的代码：
＆lt; img src =“https://www.google.com/chart?chc=sites&cht=d&chdp=sites&chl=%5B%5BGoogle+Gadget'%3D20'f%5Cv'a ％5C％3D0'10 '％3D199'0'dim' ％5Cbox1'b％5CF6F6F6'fC％5CF6F6F6'eC％5C0'sk '％5C％5B％22Steeglecom + - +谷歌+网站+就像+按钮％22' ％ 5D'a％5CV％5C％3D12'f％5C％5DV％5Cta％5C％3D10 '％3D0' ％3D200 '％3D32'dim' ％5C％3D10 '％3D10' ％3D200 '％3D32'vdim' ％ 5Cbox1'b％5Cva％5CF6F6F6'fC％5CC8C8C8'eC％5C'a％5C％5Do％5CLauto'f％5C＆amp; sig = adcK6vIIXtgjrIIlMyRBX2yiuVI“data-igsrc =”http://86.gmodules.com/ig/ifr ？中期= 86＆安培; synd = trogedit＆安培; URL = HTTP％3A％2F％2Fhosting.gmodules.com％2Fig％2Fgadgets％2Ffile％2F110509162544058635853％2Fsteegle-谷歌站点Facebook的样button.xml＆安培; up_url = www.freeeducationleague .org＆amp; up_layout = standard＆amp; up_width =＆amp; up_showfaces = false＆amp; up_action = like＆amp; up_font = arial＆amp; up_colorscheme = light＆amp; h = 35＆amp; w = 200“data-type =”ggs-gadget“data-props =”screenshot ：HTTP＃58 // www.steegle.com /图像/实样120x60.png;网址：HTTP＃58 // hosting.gmodules.com / IG /小工具/文件/ 110509162544058635853 / steegle-克oogle站点Facebook的样button.xml; PARAMS：up_url = www.freeeducationleague.org＆安培; up_layout =标准＆安培; up_width =安培; up_showfaces =假安培; up_action =像＆安培; up_font = Arial字体＆安培; up_colorscheme =光;对齐：; borderTitle ：Steegle.com - Google Sites Like Button;高度：35; igsrc：http＃58 // 95.gmodules.com / ig / ifr？mid = 95＆amp; synd = trogedit＆amp; url = http％3A％2F％2Fhosting.gmodules .COM％2Fig％2Fgadgets％2Ffile％2F110509162544058635853％2Fsteegle，谷歌的网站，Facebook的样button.xml和放大器; up_url = www.freeeducationleague.org;中期：95;滚动：无; showBorder：假; showBorderTitle：空;规范：HTTP＃58 // hosting.gmodules.com / IG /小工具/文件/ 110509162544058635853 / steegle-谷歌站点Facebook的样button.xml; up_url：www.freeeducationleague.org;宽度：200;包裹物：真;标题：Steegle.com - Google Sites Like Button“width =”200“height =”35“style =”display：inline; float：right; margin：5px 0 5px 20px;“类= “IgM的” ＆GT;