Question

我尝试使用yii框架制作网站，并制作友好的网址。在如果我使用友好的网址，如：

http://localhost/eshops/     -> calls protected/controllers/SiteController->actionIndex()
http://localhost/eshops/login -> calls protected/controllers/SiteController->actionLogin()
http://localhost/eshops/logout -> calls protected/controllers/SiteController->actionLogout()
 ...

但是如何使用另一个控制器AbcController，如

http://localhost/eshops/abc/a -> calls protected/controllers/AbcController->actionA()
http://localhost/eshops/abc/b -> calls protected/controllers/AbcController->actionB()

它没有显示“错误404”？

.htaccess是

Options +FollowSymLinks
IndexIgnore */*
RewriteEngine on
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . index.php

规则在protected / config / main.php

中

'urlManager'=>array(
    'urlFormat'=>'path',
    'showScriptName'=>false,
    'caseSensitive'=>false,
    'rules'=>array(
        'gii'=>'gii',
        '<action>'=>'site/<action>',
        '<controller:\w+>/<id:\d+>'=>'<controller>/view',
        '<controller:\w+>/<action:\w+>/<id:\d+>'=>'<controller>/<action>',
        '<controller:\w+>/<action:\w+>'=>'<controller>/<action>',
    ),
),

谢谢

Answer 1

你需要记住执行规则的顺序！您只需设置正确的规则

即可

'rules'=>array(
        'gii'=>'gii',
        '<controller:\w+>/<id:\d+>'=>'<controller>/view',
        '<controller:\w+>/<action:\w+>/<id:\d+>'=>'<controller>/<action>',
        '<controller:\w+>/<action:\w+>'=>'<controller>/<action>',
        '<action:(login|logout|register|contact)>' => 'site/<action>',
//      or full access 
//      '<action:\w+>' => 'site/<action>',
    ),

Yii-1.1.12框架，使用另一个控制器

1 个答案: